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3 years ago

I NEED HELP PLEASE, THANKS! :)

Chemistry

1 answer:

konstantin123 [22]3 years ago

7 0

Answer:

Gasoline isn't a pure substance.

Explanation:

A typical boiling range for gasoline is 100–400F. Gasoline has a vapor pressure of 7 psi in the summer, comparing it to water pressure it's less then 0.3 psi. For example if you spill water on a flat surface it might take a few minutes or hours to completly evapourate. Gasoline on the other hand it will evapurate within a few minutes, that's an example of volatility. Hope this helps

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<span>mass He = 13.0 mol x 4.00 g/mol = 52.0 g</span>

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3 years ago

A 1.24g sample of a hydrocarbon, when completely burned in an excess of O2 yields 4.04g Co2 and 1.24g H20. Draw plausible struct

arsen [322]

Answer:

Plausible structure has been given below

Explanation:

Molar mass of $CO_{2}$ is 44 g/mol and molar mass of $H_{2}O$ is 18 g/mol
Number of mole = (mass/molar mass)

4.04 g of $CO_{2}$ = $\frac{4.04}{44}moles$ $CO_{2}$ = 0.0918 moles of $CO_{2}$

1 mol of $CO_{2}$ contains 1 mol of C atom

So, 0.0918 moles of $CO_{2}$ contains 0.0918 moles of C atom

1.24 g of $H_{2}O$ = $\frac{1.24}{18}moles$ $H_{2}O$ = 0.0689 moles of $H_{2}O$

1 mol of $H_{2}O$ contain 2 moles of H atom

So, 0.0689 moles of $H_{2}O$ contain $(2\times 0.0689)moles$ of $H_{2}O$ or 0.138 moles of $H_{2}O$

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is $C_{2}H_{3}$

So, molecular formula of one of it's analog is $C_{4}H_{6}$

Plausible structure of $C_{4}H_{6}$ has been given below.

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2 years ago

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3 years ago

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Answer:

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3 years ago