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Illusion [34]
3 years ago
9

I NEED HELP PLEASE, THANKS! :)

Chemistry
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

Gasoline isn't a pure substance.

Explanation:

A typical boiling range for gasoline is 100–400F. Gasoline has a vapor pressure of 7 psi in the summer, comparing it to water pressure it's less then 0.3 psi. For example if you spill water on a flat surface it might take a few minutes or hours to completly evapourate. Gasoline on the other hand it will evapurate within a few minutes, that's an example of volatility.  Hope this helps

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I need part 1 and 2 please , just separate answers
Vladimir79 [104]

First, we have to remember the molarity formula:

M=\text{ }\frac{moles\text{ of solute}}{L\text{ solution}}

Part 1:

In this case, our solute is sodium nitrate (NaNO3), and we have the mass dissolved in water, then we have to convert grams to moles. For that, we need the molecular weight:

M.W_{NaNO_3}=\text{ 23+14+16*3= 85 g/mol}

Then, we calculate the moles present in the solution:

3.976\text{ g NaNO}_3\text{ * }\frac{1\text{ mol}}{85\text{ g}}=\text{ 0.04678 mol NaNO}_3

Now, we have the necessary data to calculate the molarity (with the solution volume of 200 mL):

M=\frac{0.04678\text{ mol}}{200\text{ mL*}\frac{1\text{ L}}{1000\text{ mL}}}=\text{ 0.2339 M}

The molarity of this solution equals 0.2339 M.

Part 2:

In this case, we have the same amount (in moles and mass) of sodium nitrate, but a different volume of solution, then we only have to change it:

M=\text{ }\frac{0.04678\text{ mol}}{275\text{ mL *}\frac{1\text{ L}}{1000\text{ mL}}}=\text{ 0.1701 M}

So, the molarity of this solution is 0.1701 M.

5 0
1 year ago
You have two sealed jars of water at the same temperature. In the first jar there is a large amount of water. In the second jar
melisa1 [442]

since both the jars are kept at the same temperature the vapor pressure will be same in both the cases.


3 0
3 years ago
A sample of a compound is determined to have 1.17 g of carbon and 0.287 g of hydrogen. what is the correct representation of the
yarga [219]

CH3 is the empirical formula for the compound.

A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.

The number of atom or moles in the compound is

1.17 g C X  1 mol of C / 12.011 g C = 0.097411 mol of C.

0.287 g H x 1 mol of  H / 1 g H = 0.28474 mol H.

This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.

So we can represent the compound with the formula C0.974H0.284.

Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.

we can divide 0.284 by 0.0974.

0.284 / 0.0974 = 3.

So here, Carbon is one and hydrogen is 3.

We can write the above formula as a CH3.

Hence the empirical formula for the sample compound is CH3.

For a detailed study of the empirical formula refer given link brainly.com/question/13058832.

#SPJ1.

5 0
2 years ago
How many moles are in 432 g of Ba(NO3)2?
Artist 52 [7]

Answer:

432/261.337=1.65 moles

Explanation:

4 0
3 years ago
How are endothermic and exothermic reactions the same how are they different?
svetoff [14.1K]

Endothermic reactions and Exothermic reaction are never the same.

They are both different.

Definitions

<span><span>Endothermic:- reactions that take in energy. For example:- electrolysis, thermal decomposition and the reaction between ethanic acid and sodium carbonate.
</span><span>Exothermic:- reactions that transfer energy to the surroundings. For example:- burning, neutralisation and the reaction between water and calcium oxide.</span></span>
3 0
3 years ago
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