Answer:
25 g/hr
Explanation:
Remember that the rate of reaction refers to the rate at which reactants are used up or or the rate at which products appear.
Hence;
Rate of reaction = mass of reactant used up/time taken
Mass of reactant used up= 2g
Time taken = 5 minutes or 0.08 hours
Rate of reaction = 2g/0.08 hours = 25 g/hr
Answer:
Mass = 5.92 g
Explanation:
Given data:
Volume of O₂ = 4.15 mol
Temperature and pressure = standard
Mass in gram = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
By putting values,
1 atm × 4.15L = n ×0.0821 atm.L /mol.K × 273.15 k
4.15 atm.L = n ×22.43 atm.L /mol
n = 4.15 atm.L / 22.43 atm.L /mol
n = 0.185 mol
Mass in gram:
Mas = number of moles × molar mass
Mass = 0.185 mol ×32g/mol
Mass = 5.92 g
Answer:
I just guessed it out to be 3
Answer:
C₄H₁₂
Explanation:
The empirical formula gives you your smallest whole number ratio for the elements in the compound. Find the molar mass using a periodic table. We have one carbon (12.01 g/mol) and three hydrogens (1.008 g/mol). Therefore our molar mass for the empirical formula is 12.01 + 3(1.008) = 15.034 g/mol. To find the molecular formula divide the given molar mass by the empirical formula's molar mass 60.2/15.034 = 4.004257017 = 4. This number is the amount to multiply the empirical formula by to get the molecular formula, therefore your molecular formula is C₄H₁₂
