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3 years ago

PLEASE HELP!!! (Look at photo)

Chemistry

1 answer:

pychu [463]3 years ago

7 0

Answer

element

Explanation:

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What is the balanced chemical equation for the reaction of sodium and oxygen?Na + O to NaO2Na + O2 to 2 NaO4Na + O2 to 2Na2ONa +

zavuch27 [327]

Answer

4Na + O₂ → 2Na₂O

Explanation

Sodium reacts with oxygen to form sodium oxide and has the following balanced chemical equation:

4Na + O₂ → 2Na₂O.

Hence, the balanced chemical equation for the reaction of sodium and oxygen is:

4Na + O2 to 2Na2O

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1 year ago

Identify the medium for the following waves:

Serjik [45]

1. I don't understand what wave exercise waves are?

2. Water is the medium.

3. Air is the medium.

4. The Earth or ground is the medium.

(I think these are right, as the medium is what they are travelling through.)

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3 years ago

What is one benefit that nuclear power plants currently provide for our environment?

liubo4ka [24]

Explanation:

Nuclear power plants deliver electricity 24 hours a day, 7 days a week, irrespective of weather and seasons. As well as reducing greenhouse gas emissions, nuclear generation helps reduce air pollution

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3 years ago

Read 2 more answers

The concentration in (M) of bromide ions ina

Anon25 [30]

Answer : The concentration in (M)of bromide ions in a saturated solution of mercury (II) bromide is, $2.7\times 10^{-7}M$

Explanation :

The solubility equilibrium reaction will be:

$HgBr_2\rightleftharpoons Hg^{2+}+2Br^{-}$

Let the molar solubility be 's'.

The expression for solubility constant for this reaction will be,

$K_{sp}=[Hg^{2+}][Br^{-}]^2$

$K_{sp}=(s)\times (2s)^2$

$K_{sp}=4s^3$

Given:

$K_{sp}$ = $8.0\times 10^{-20}$

Now put all the given values in the above expression, we get:

$K_{sp}=4s^3$

$8.0\times 10^{-20}=4s^3$

$s=2.7\times 10^{-7}M$

Therefore, the concentration in (M)of bromide ions in a saturated solution of mercury (II) bromide is, $2.7\times 10^{-7}M$

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3 years ago

In which of the following are the symbols and names for the ions given correctly?

Ne4ueva [31]

Answer: Option (A) is the correct answer.

Explanation:

The name of $OH^{-}$ ion is hydroxide.

Name of $PO^{3-}_{3}$ ion is phosphite.

Name of $PO^{3-}_{4}$ ion is phosphate.

Name of $NH^{+}_{4}$ ion is ammonia.

Name of $C_{2}H_{3}O_{2}^{-}$ ion is acetate.

Name of $C_{2}O_{4}^{-}$ ion is oxalate.

Thus, we can conclude that the symbols and names for the ions given correctly is OH-:hydroxide

4 0

4 years ago