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Jobisdone [24]
3 years ago
10

A 5Kg ball rolling to the right at a velocity of 5m/s hits a stationary 10Kg ball. It is an elastic collision and the final velo

city of the 5Kg ball is 0m/s. What is the final velocity of the 10Kg ball?
Physics
1 answer:
exis [7]3 years ago
7 0

Answer:

magnitude of v = 2.5 m/s, and in the same direction as the initial velocity of the 5 kg ball.

Explanation:

We use conservation of linear momentum in an elastic collision to solve for the unknown velocity v:

Pi = Pf

5 kg * 5 m/s + 10 kg * 0 m/s = 5 kg * 0 m/s + 10 kg * v

25 kg m/s = 10 kg * v

v = 25/10 m/s

v = 2.5 m/s

and in the same direction as the initial velocity of the 5 kg ball.

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If energy is absorbed because chemical reaction is ______.
melomori [17]
<h2>Answer:</h2>

The reaction is <u>D. endothermic</u>.

<h2>Explanation:</h2>

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3 years ago
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7 0
3 years ago
A girl with a mass of 27 kg is playing on a swing. There are three main forces
N76 [4]

The tension in the swing's chain at the bottom of the swing is 178.35 N.

The given parameters:

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  • Speed of the girl, v = 3 m/s
  • Radius of the circle, r = 4 m

The tension in the swing's chain at the bottom of the swing is calculated as follows;

T = mg + ma_c\\\\ T= mg + \frac{mv^2}{r} \\\\T = (12 \times 9.8) + (\frac{27 \times 3^2}{4} )\\\\T = 117.6 \ N \ + \ 60.75 \ N\\\\T = 178.35 \ N

Thus, the tension in the swing's chain at the bottom of the swing is 178.35 N.

Learn more about tension in vertical circle here: brainly.com/question/19904705

3 0
2 years ago
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