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asambeis [7]
3 years ago
9

If a coil is rotated in a magnetic field at twice the speed -- ie twice the frequency -- the amplitude of the EMF induced in the

loop will...
A. remain unchaged

B. reduce by half

C. double
Physics
1 answer:
valkas [14]3 years ago
6 0

Answer:

C. double

Explanation:

The voltage of a EMF depends largely on the amount of spins that the coild is able to do, in this case as yuo are doubling the speed at which the coil is rotating you are also doubling the number of spins that the coil is doing in a certain amount of time, so the amplitude of the EMF induce on the loop will also double.

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A linear accelerator produces a pulsed beam of electrons. The pulse current is 0.50 A, and the pulse duration is 0.10 μs. (a) Ho
Crank

Answer:

a)N = 3.125 * 10¹¹

b) I(avg)  = 2.5 × 10⁻⁵A

c)P(avg) = 1250W

d)P = 2.5 × 10⁷W

Explanation:

Given that,

pulse current is 0.50 A

duration of pulse Δt = 0.1 × 10⁻⁶s

a) The number of particles equal to the amount of charge in a single pulse divided by the charge of a single particles

N = Δq/e

charge is given by Δq = IΔt

so,

N = IΔt / e

N = \frac{(0.5)(0.1 * 10^-^6)}{(1.6 * 10^-^1^9)} \\= 3.125 * 10^1^1

N = 3.125 * 10¹¹

b) Q = nqt

where q is the charge of 1puse

n = number of pulse

the average current is given as I(avg) = Q/t

I(avg) = nq

I(avg) = nIΔt

         = (500)(0.5)(0.1 × 10⁻⁶)

         = 2.5 × 10⁻⁵A

C)  If the electrons are accelerated to an energy of 50 MeV, the acceleration voltage must,

eV = K

V = K/e

the power is given by

P = IV

P(avg) = I(avg)K / e

P(avg) = \frac{(2.5 * 10^-^5)(50 * 10^6 . 1.6 * 10^-^1^9)}{1.6 * 10^-^1^9}

= 1250W

d) Final peak=

P= Ik/e

= = P(avg) = \frac{(0.5)(50 * 10^6 . 1.6 * 10^-^1^9)}{1.6 * 10^-^1^9}\\2.5 * 10^7W

P = 2.5 × 10⁷W

5 0
3 years ago
Read 2 more answers
At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.5 m/s2. At the same insta
Licemer1 [7]

Answer:

6.96 s

Explanation:

<u>Given:</u>

  • u = initial speed of the automobile = 0 m/s
  • a = constant acceleration of the automobile = 2.5\ m/s^2
  • v = constant speed of the truck = 8.7 m/s

<u>Assume:</u>

  • t = time instant at which the automobile overtakes the truck.

At the moment the automobile and the truck both meat each other the distance travel by both vehicles must be the same.

\therefore \textrm{Distance traveled by the automobile }=\textrm{Distance traveled by the truck}\\\Rightarrow ut+\dfrac{1}{2}at^2=vt\\\Rightarrow (0)t+\dfrac{1}{2}\times 2.5\times t^2=8.7t\\\Rightarrow 1.25t^2=8.7t\\\Rightarrow 1.25t^2-8.7t=0\\\Rightarrow t(1.25t-8.7)=0\\\Rightarrow t = 0\,\,\,or\,\,\, t = \dfrac{8.7}{1.25}\\\Rightarrow t = 0\,\,\,or\,\,\, t = 6.96\\

Since t = 0 s is the initial condition. So, they both meet again at t = 6.96 s such that the automobile overtakes the truck.

6 0
3 years ago
Can someone help me please
TEA [102]

Answer:

D

Explanation:

Because it is impossible for it to show the real depth of the ocean and how deep it is

8 0
3 years ago
A baseball pitcher throws a ball across home plate. The ball travels 13.40m in 0.357s Determine the
Tanya [424]

Answer: I'm not sure what it needs to be rounded to, but I got 37.53501401 m/s

Explanation: The formula for speed is speed = distance/time. You plug in the distance (13.40) and the time (0.357), then divide 13.40 by 0.357

I hope this helps! :)

4 0
2 years ago
Mr. Fuller assigned his science class a lab comparing the masses of objects to the nearest gram using a balance. The mass of a p
Tomtit [17]
The scale would need 10 aluminum cubes on one side. Figure out how many paper clips would be needed on the other side to balance this. You have to use more than one aluminum cube because you need to have enough cubes so that you get a whole number mass. 10 cubes gives you a total mass of 27 g for the aluminum.
5 0
3 years ago
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