Technician A says that side post terminals need to be removed to inspect them for corrosion. Technician B says that side post te
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Given:
heat generated by John's cooling system, = 45 W (1)
If ρ, A, and v corresponds to John's cooling system then let be the variables for Mike's system then:
Formula use:
Heat generated,
where,
= density
A = area
v = velocity
Solution:
for Mike's cooling system:
=
⇒ =
× A ×
= 4.513
A
Using eqn (1) in the above eqn, we get:
= 4.513 × 45 = 203.09 W
Explanation:
(a) Formula to calculate volume of the submerged wooden block is as follows.
It is given data of the wooden block is as follows.
depth = 7.96 cm, length (l) = 6 cm
width (w) = 4 cm,
So, we will calculate the volume of the submerged wooden block as follows.
=
= 286.56
Hence, the submerged volume of the block is 286.56 .
(b) Expression for the buoyant force acting on the wooden block is as follows.
And, expression for the force of gravity of the wooden block is as follows.
As the wooden block is floating on the water hence, buoyant force is balanced by the weight of the block.
Hence, mass of the wooden block will be calculated as follows.
=
=
= 0.02857 kg
Therefore, mass of the given block is 0.02857 kg
(c) Expression for the density of the block is as follows.
Now, expression for the total volume of the wooden block is as follows.
Hence, density of the given block is as follows.
=
=
=
Therefore, density of the given block is .