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jonny [76]
3 years ago
14

When it goes through a chemical change, a substance changes what

Physics
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

form

I'm pretty sure...

let me know if I'm right, if I am give brainliest

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In the figure below (Figure 1), the upper ball is released from rest, collides with the stationary lower ball, and sticks to it.
Georgia [21]

(a) The frequency of the motion after the collision is 0.71 Hz.

(b) The maximum angular displacement of the motion after the collision is 16.3⁰.

<h3>Speed of the 2.2 kg ball when it collides with 2.7 kg ball</h3>

The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 0.1)

v = 1.4 m/s

<h3>Final speed of both balls after collision</h3>

The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.

Pi = Pf

m₁v₁ + m₂v₂ = vf(m₁ + m₂)

2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)

3.08 = 4.9vf

vf = 3.08/4.9

vf = 0.63 m/s

<h3>Maximum displacement of the balls after the collision</h3>

P.E = K.E

mgh_f = \frac{1}{2} mv_f^2\\\\h_f = \frac{v_f^2}{2g} \\\\h_f = \frac{(0.63)^2}{2(9.8)} \\\\h_f = 0.02 \ m

<h3>Maximum angular displacement</h3>

The maximum angular displacement of the balls after the collision is calculated as follows;

cos \theta = \frac{L - h_f}{L} \\\\cos\theta = \frac{0.5 - 0.02}{0.5} \\\\cos\theta = 0.96\\\\\theta = cos^{-1}(0.96)\\\\\theta = 16.3 \ ^0

<h3>Frequency of the motion</h3>

f = \frac{1}{2\pi} \sqrt{\frac{g}{L} } \\\\f = \frac{1}{2\pi } \sqrt{\frac{9.8}{0.5} } \\\\f = 0.71 \ Hz

Learn more about maximum angular displacement here: brainly.com/question/13665036

4 0
2 years ago
Which statement best describes how the phase of the Moon changes from a nev, moon to a
erastova [34]

Answer:

It is C

Explanation:

mark me brainliest please

8 0
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