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jonny [76]
3 years ago
14

When it goes through a chemical change, a substance changes what

Physics
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

form

I'm pretty sure...

let me know if I'm right, if I am give brainliest

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Homogous chromosomes separate during.....?
stepladder [879]
Not entirely sure if you're saying Homologous , but assuming you do , the homologous chromosomes seperate in the anaphase stage of Mitsosis of the Cell cycle
3 0
3 years ago
TRANSFORMA: 765 mm Hg a atm
-Dominant- [34]

Presión

765

=

ATMÓSFERA

1,00658

Answer:

Explanation:

5 0
3 years ago
The Z0 boson, discovered in 1985, is the mediator of the weak nuclear force, and it typically decays very quickly. Its average r
Dvinal [7]

Answer:

The lifetime of the particle is  \Delta  t  =  2.6*10^{-25} \ s

Explanation:

From the question we are told that

    The average rest energy is E =  91.19 \ GeV =  91.19GeV  *    \frac{1.60 *10^{-10} J }{1GeV} = 1.46 *10^{-8}J

    The intrinsic width is  \Delta E  =2.5eV  = 2.5GeV   *  \frac{1.60 *10^{-10}J  }{1GeV}  =  4*10^{-10} J

The lifetime is mathematically represented as

     \Delta  t  =  \frac{h}{\Delta E}

Where h is the Planck's constant with a value of  1.055*10^{-34} \ J\cdot s  

substituting values

    \Delta  t  =  \frac{1.055*10^{-34}}{4 *10^{-10}}

     \Delta  t  =  2.6*10^{-25} \ s

6 0
2 years ago
How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 4.00
klio [65]

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is 9 \times 10^{-4} m^{2}. As the capacitance of capacitor is given as follows.

            C = \frac{\epsilon_{o}A}{d}

It is known that the dielectric strength of air is as follows.

               E = 3 \times 10^{6} V/m

Expression for maximum potential difference is that the capacitor can with stand is as follows.

                       dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

               Q = CV

                   = \frac{\epsilon_{o} A}{d} \times E \times d

                   = \epsilon_{o}AE

                   = 8.85 \times 10^{-12} \times 3 \times 10^{6} \times 4 \times 10^{-4}

                   = 1.062 \times 10^{-8} C

or,                = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

5 0
3 years ago
If you are involved in any type of collision, it is important you
o-na [289]
If you are involved in a collision, it's important that you stop your car and protect others, as well as your self, from oncoming traffic. If you do not stop, you will have an arrest warrant against your name as it can safely be considered a 'hit and run.' 
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