Answer:
a) ![v=0.999124c](https://tex.z-dn.net/?f=v%3D0.999124c)
b) ![E=7.566*10^{22}](https://tex.z-dn.net/?f=E%3D7.566%2A10%5E%7B22%7D)
c) ![E_a=760 times\ larger](https://tex.z-dn.net/?f=E_a%3D760%20times%5C%20larger)
Explanation:
From the question we are told that
Distance to Betelgeuse ![d_b=430ly](https://tex.z-dn.net/?f=d_b%3D430ly)
Mass of Rocket ![M_r=20000](https://tex.z-dn.net/?f=M_r%3D20000)
Total Time in years traveled ![T_d=36years](https://tex.z-dn.net/?f=T_d%3D36years)
Total energy used by the United States in the year 2000 ![E_{2000}=1.0*10^20](https://tex.z-dn.net/?f=E_%7B2000%7D%3D1.0%2A10%5E20)
Generally the equation of speed of rocket v mathematically given by
![v=\frac{2d}{\triangle t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B2d%7D%7B%5Ctriangle%20t%7D)
![v=860ly/ \triangle t](https://tex.z-dn.net/?f=v%3D860ly%2F%20%5Ctriangle%20t)
where
![\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}](https://tex.z-dn.net/?f=%5Ctriangle%20t%3D%5Cfrac%7B%5Ctriangle%20t%27%7D%7B%28%5Csqrt%7B1-860%2F%20%5Ctriangle%20t%29%5E2%7D%7D)
![\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}](https://tex.z-dn.net/?f=%5Ctriangle%20t%3D%5Cfrac%7B36%7D%7B%28%5Csqrt%7B1-860%2F%20%5Ctriangle%20t%29%5E2%7D%7D)
![\triangle t=\sqrt{(860)^2+(36)^2}](https://tex.z-dn.net/?f=%5Ctriangle%20t%3D%5Csqrt%7B%28860%29%5E2%2B%2836%29%5E2%7D)
![\triangle t=860.7532](https://tex.z-dn.net/?f=%5Ctriangle%20t%3D860.7532)
Therefore
![v=\frac{860ly}{ 860.7532}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B860ly%7D%7B%20860.7532%7D)
![v=0.999124c](https://tex.z-dn.net/?f=v%3D0.999124c)
b)
Generally the equation of the energy E required to attain prior speed mathematically given by
![E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%28v%2Fc%29%5E2%7D%20%7D-1%2820000kg%29%283%2A10%5E8m%2Fs%29%5E2)
![E=7.566*10^{22}](https://tex.z-dn.net/?f=E%3D7.566%2A10%5E%7B22%7D)
c)Generally the equation of the energy
required to accelerate the rocket mathematically given by
![E_a=\frac{E}{E_{2000}}](https://tex.z-dn.net/?f=E_a%3D%5Cfrac%7BE%7D%7BE_%7B2000%7D%7D)
![E_a=\frac{7.566*10^{22}}{1.0*10^{20}}](https://tex.z-dn.net/?f=E_a%3D%5Cfrac%7B7.566%2A10%5E%7B22%7D%7D%7B1.0%2A10%5E%7B20%7D%7D)
![E_a=760 times\ larger](https://tex.z-dn.net/?f=E_a%3D760%20times%5C%20larger)
Electrostatic forces between charges depend on the product of
the sizes of the charges, and the distance between them.
We should also mention the item about whether the charges are
both the same sign or opposite signs. That determines whether
the forces will pull them together or push them apart, which is a
pretty significant item.
Answer:
ntergalactic space takes up most of the volume of the universe, but even galaxies and star systems consist almost entirely of empty space.
Explanation:
so to be exact galixes do make up most of the volume of space because galaxies are what make up space!
Answer:
Good Luck!
Follow Me
<h2><u><em>
D</em></u></h2>
Explanation:
3) For a displacement time graph, straight line denotes constant speed. For a velocity time graph, the graph parallel to time axis denotes constant speed. Hence, the correct option is a) and d).
Answer:
cm
Explanation:
= separation between the slits = 2783 x 10⁻⁹ m
= wavelength of coherent light = 644 nm = 644 x 10⁻⁹ m
= Distance of the screen = 6 cm = 0.06 m
= Position of nth bright fringe
Position of nth bright fringe is given as
for n = 2
![y_{2} = \frac{(2)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}](https://tex.z-dn.net/?f=y_%7B2%7D%20%3D%20%5Cfrac%7B%282%29%280.06%29%28644%5Ctimes10%5E%7B-9%7D%29%29%7D%7B2783%5Ctimes10%5E%7B-9%7D%7D)
m
for n = 4
![y_{4} = \frac{(4)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}](https://tex.z-dn.net/?f=y_%7B4%7D%20%3D%20%5Cfrac%7B%284%29%280.06%29%28644%5Ctimes10%5E%7B-9%7D%29%29%7D%7B2783%5Ctimes10%5E%7B-9%7D%7D)
m
Distance between 4th and 2nd bright fringes is given as
![w = y_{4} - y_{2} = 0.0555 - 0.0278 = 0.0277 m](https://tex.z-dn.net/?f=w%20%3D%20y_%7B4%7D%20-%20y_%7B2%7D%20%3D%200.0555%20-%200.0278%20%3D%200.0277%20m)
cm