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jonny [76]
3 years ago
14

When it goes through a chemical change, a substance changes what

Physics
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

form

I'm pretty sure...

let me know if I'm right, if I am give brainliest

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You pick up a 3.4-kg can of paint from the ground and lift it to a height of 1.8 m. (a) how much work do you do on the can of pa
MariettaO [177]

(a) For the work-energy theorem, the work done to lift the can of paint is equal to the gravitational potential energy gained by it, therefore it is equal to

W=mg\Delta h

where m=3.4 kg is the mass of the can, g=9.81 m/s^2 is the gravitational acceleration and \Delta h=1.8 m is the variation of height. Substituting the numbers into the formula, we find

W=(3.4 kg)(9.81 m/s^2)(1.8 m)=60.0 J


(b) In this case, the work done is zero. In fact, we know from its definition that the work done on an object is equal to the product between the force applied F and the displacement:

W=Fd

However, in this case there is no displacement, so d=0 and W=0, therefore the work done to hold the can stationary is zero.


(c) In this case, the work done is negative, because the work to lower the can back to the ground is done by the force of gravity, which pushes downward. Its value is given by the same formula used in part (a):

W=mg \Delta h=(3.4 kg)(9.81 m/s^2)(-1.8 m)=-60.0 J

8 0
4 years ago
Two 3 kg spherical masses are connected by a 20 m long thread of negligible mass that does not stretch. The masses are charged s
Yuri [45]

Answer:

The charge of each sphere is  q = - 1.84 *10^{-4}C

Explanation:

 The  free body diagram of this question is shown on the first uploaded image  

       From the question we are told that

            The mass of the two sphere is m = 3 \ kg

             The length of the connection is l  = 20\ m

              The angle between the suspended side is  \theta = 17 ^o

At Equilibrium the force acting at the horizontal is  = 0N and the net force acting at the vertical is zero

    This can be represented mathematically as

                 \sum F_y = 0N , \ \ and \ \  \sum F_x = 0N

For  \sum F_y = 0N

      T cos \theta = mg

=>     cos \theta  = \frac{mg}{T}

   For  \sum F_x = 0N

        T sin \theta  = F

=>   sin \theta = \frac{F}{T}

     Now  tan \theta  = \frac{sin \theta }{cos \theta }

                       = \frac{\frac{F}{T} }{\frac{mg}{T} }

                       = \frac{F}{mg}                    

Where F is the electrical force which is mathematically represented as

           F = \frac{kq^2}{r^2}

Therefore

           tan \theta = \frac{kq^2}{mgr^2}

 Where r is the distance between the two masses and from the diagram it is

    r = 2l sin \theta

So

      tan \theta = \frac{kq^2 }{(2l sin \theta )^2 * mg}

making q the subject of the formula  

               q = \sqrt{\frac{mg}{k} * tan \theta  (2l sin \theta )^2 }

Where k is  the Coulomb's constant with a value of   k = 9*10^{9} kg \ cdot m^3 s^{-4} A^{-2}

  Substituting values

           q = \sqrt{\frac{3 * 9.8 }{9*10^9} * tan (17) (20 sin 17)^2 }

               q = - 1.84 *10^{-4}C

The negative sign is because we are told from the question that they are negatively charged

                       

           

8 0
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Danny is competing in the high jump.
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Answer:

D. potential; kinetic

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Fever is used by your body to fight all of the following except
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Answer is a cut from a knife
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Scientists have learned about the structure of Earth's interior by
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C) studying seismic waves

AKA what is studied from earthquakes
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