Answer: coefficient of static friction
= 0.31
Explanation: Since they negotiate the curve without skidding, the frictional force (F1) equals the centripetal force (F2).
F1= uN
F2 = M*(v²/r)
M is the combined mass 450kg
V is the velocity 18m/s
r is the radius 106m
N is the normal reaction 4410N
u is the coefficient of static friction
Making u subject of the formula we have that,
u = {450*(18²/106)} /4410
=1375.47/4410
=0.31
NOTE: coefficient of friction is dimensionless. It as no Unit.
Answer:
0.75 m³/s
Explanation:
Applying,
Q = vA.................... Equation 1
Where Q = flow rate of the water, v = velocity of the water, A = area of the pipe.
From the question,
Given: v = 2.5 m/s, A = 0.3 m²
Substitute these values into equation 1
Q = 2.5(0.3)
Q = 0.75 m³/s
Hence the flow rate of water in the pipe is 0.75 m³/s
Answer: 0.076 m/s
Explanation:
Momentum is conserved:
m v = (m + M) V
(0.111 kg) (55 m/s) = (0.111 kg + 80. kg) V
V = 0.076 m/s
After catching the puck, the goalie slides at 0.076 m/s.
The moon is 230,100 miles from planet earth.
Answer:
Change in potential energy is 700.7 J.
Explanation:
Given:
Mass of the object is,
kg
Height to which the object is raised above his head,
m
Acceleration due to gravity is,
m/s²
We know that for a mass
raised to a height
, the change in potential energy is given as:
, where, 
Now, plug in the given values and solve.

Therefore, the change in the potential energy is 700.7 J.