Since each of the substances conduct electricity except A, it is the least likely to be metallic. Additionally, it is a powder, which is unlike most metals, and has an extremely high melting point much above many metal substances and very different from the other substances tested.
When you assume that the gas is behaving ideally, the gas molecules are very far from each other that they do not have any intermolecular forces. If it behaves this way, you can assume the ideal gas equation:
PV = nRT, where
P is the pressure
V is the volume
n is the number of moles
R is a gas constant
T is the absolute temperature
When the process goes under constant pressure (and assuming same number of moles),
P/nR = T/V = constant, therefore,
T₁/V₁=T₂/V₂
If V₂ = V₁(1+0.8) = 1.8V₁, then,
T₂/T₁ = 1.8V₁/V₁
Cancelling V₁,
T₂/300=1.8
T₂ =540 K
If you do not assume ideal gas, you use the compressibility factor, z. The gas equation would now become
PV =znRT
However, we cannot solve this because we don't know the value of z₁ and z₂. There will be more unknowns than given so we won't be able to solve the problem. But definitely, the compressibility factor method is more accurate because it does not assume ideality.
<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ
<u>Explanation:</u>
To calculate the mass of water, we use the equation:
Density of water = 1 g/mL
Volume of water = 1.50 L = 1500 mL (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
To calculate the heat absorbed by the water, we use the equation:
where,
q = heat absorbed
m = mass of water = 1500 g
c = heat capacity of water = 4.186 J/g°C
= change in temperature = 
Putting values in above equation, we get:
Hence, the amount of heat required to warm given amount of water is 470.9 kJ
An isomer is a compound that differs by another based on either the molecular connectivity or how the atoms are connected to each other in the compound, or by stereochemistry usually.
I believe there are total number of 5 isomers for the compound of C6H14. Hexane.
0.0024 g of Ba(NO₃)₂
Explanation:
First we need to determine the molecular weight of barium nitrate Ba(NO₃)₂
molecular wight of Ba(NO₃)₂ = molecular weight of Ba × number of Ba atoms + molecular weight of N × number of N atoms + molecular weight of O × number of O atoms
molecular wight of Ba(NO₃)₂ = 137 × 1 + 14 × 2 + 16 × 6 = 261 g/mol
number of moles = mass / molecular weight
mass = number of moles × molecular weight
mass of Ba(NO₃)₂ = 0.625 / 261 = 0.0024 g
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moles
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