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lukranit [14]
3 years ago
11

Write a linear equation using the points on the graph. y=mx+b

Mathematics
2 answers:
bonufazy [111]3 years ago
8 0

Answer:

y = 2x + 4

Step-by-step explanation:

By using the x and y intercepts, you can come up with your linear equation.

X-I is -2 at point (-2,0)

Y-I is 4 at point (0,4)

therefore the answer is

y = 2x + 4

hope this is right and it helps you :)

Sauron [17]3 years ago
8 0
Y=2x+4 because that’s what the other person said
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10. If log10x = 1 + a and log10y = 1 – a, show that xy = 100.<br> How?
gregori [183]

Step-by-step explanation:

log x = 1 + a

a = log x - 1

log y = 1 - a

a = 1 - log y

So

log x - 1 = 1 - log y

log x + log y = 2

log (xy) = 2

xy = 100

7 0
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GUYS PLEASE HELP MY TEACHER SKIPPED A WHOLE CHAPTER I ONLY KNOW BASICS SO PLEASEEEE HELP `(*&gt;﹏&lt;*)′
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
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A train is travelling at a constant speed in ten minutes it travels 24 km work out how far it travels in 20 minutes
Elina [12.6K]
If it travels at a constant speed for twice the amount of time, the train should travel twice the distance, or 24 * 2 = 48 km.
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3 years ago
A carpenter has 16 1/2 m of wood. He cuts the wood into pieces that are each 2 3/4 m long. How many pieces of wood does the carp
NNADVOKAT [17]
Simplify the denominator so it is the same 
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4 divided by 2=2 
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1/2
Hope this helped :D! can you mark me brainliest...



5 0
4 years ago
Read 2 more answers
Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable
bekas [8.4K]

Answer:

\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

u=\frac{y}{x}

Multiply both sides by x:

ux=y

Second step: Differentiate the substitution:

u'x+u=y'

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}

u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of x^2 so I'm going to divide top and bottom by x^2:

u'x+u=\frac{u+u^2}{3+u^2}

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

u'x=\frac{u+u^2}{3+u^2}-u

Find a common denominator: Multiply second term on right hand side by \frac{3+u^2}{3+u^2}:

u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}

Combine fractions while also distributing u to terms in ( ):

u'x=\frac{u+u^2-3u-u^3}{3+u^2}

u'x=\frac{-u^3+u^2-2u}{3+u^2}

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

u' \frac{3+u^2}{-u^3+u^2-2u}x=1

Divide both sides by x:

\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}

Reorder the top a little of left hand side using the commutative property for addition:

\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}

The expression on left hand side almost matches your expression but not quite so something seems a little off.

5 0
3 years ago
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