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Furkat [3]
3 years ago
13

anyone wanna do my chem test for 500 points? my insta is niqsariot_1 hmu if your interested and for everyone else FREE 100 POINT

S
Chemistry
2 answers:
daser333 [38]3 years ago
6 0

Answer:

I would be if I do it your no learning anything but I would but I don't have insta yet

Explanation:

sorry

Luda [366]3 years ago
3 0

Answer:

k

Explanation:

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Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and
coldgirl [10]

Answer :

a. The oxidizing agent is: BH_4^-

b. The reducing agent is: ClO_3^-

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

BH_4^-(aq)+ClO_3^-(aq)\rightarrow H_2BO_3^-(aq)+Cl^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : BH_4^-\rightarrow H_2BO_3^-

Reduction : ClO_3^-\rightarrow Cl^-

Now balance oxygen atom on both side.

Oxidation : BH_4^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-  

Now balance hydrogen atom on both side.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-+6OH^-

Now balance the charge.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O+4e^-

Reduction : ClO_3^-+3H_2O+6e^-\rightarrow Cl^-+6OH^-

In order to balance the electrons, we multiply the oxidation reaction by 6 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 6BH_4^-+24OH^-\rightarrow 6H_2BO_3^-+18H_2O+24e^-

Reduction : 4ClO_3^-+12H_2O+24e^-\rightarrow 4Cl^-+24OH^-

The balanced chemical equation in acidic medium will be,

6BH_4^-+4ClO_3^-\rightarrow 6H_2BO_3^-+6H_2O+4Cl^-

3BH_4^-+2ClO_3^-\rightarrow 3H_2BO_3^-+3H_2O+2Cl^-

In the redox reaction, ClO_3^- act as oxidizing agent and BH_4^- act as an reducing agent.

7 0
3 years ago
What property of a solution remains the same after it is diluted? (3 points)
madreJ [45]

Dilution means adding more solvent to a solution to lower down its concentration and in that process volume of solution expands. That means on diluting a solution the following parameters will change:

1. Amount of solvent

2. Total volume of the solution

3.Concentration of the solution

So the parameter that does not change is the amount of solute that will remain constant on diluting a solution, So here the the answer will be the amount of solute that will remain unchanged during dilution.

6 0
3 years ago
A container of oxygen gas is at STP. If this sample is put into an oven at 280 C, what would its pressure be, in atmospheres?
Leni [432]

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial pressure (P1) = 1atm

Initial temperature (T1) = 0°C = 0°C + 273 = 273K

Final temperature (T2) = 280°C = 280°C + 273 = 553K

Final pressure (P2) =...?

Step 2:

Determination of the new pressure of the gas.

Since the volume of the gas is constant, the following equation:

P1/T1 = P2/T2

will be used to obtain the pressure. This is illustrated below:

P1/T1 = P2/T2

1/273 = P2 / 553

Cross multiply

273x P2 = 553

Divide both side by 273

P2 = 553/273

P2 = 2.03atm

Therefore, the new pressure of the gas will be 2.03atm

3 0
3 years ago
Read 2 more answers
There are three stable isotopes of magnesium. Their masses are 23.9850, 24.9858, and 25.9826 u. If the average atomic mass of ma
olganol [36]

Answer:

²⁵ Mg = 10.00%

²⁶ Mg = 11.0%

Explanation:

Given that:

Magnesium ²⁴Mg has an abundance of 78.99%

Hence, (100 - 78.99)% = 21.01%

21.01% is the abundance of ²⁵ Mg and ²⁶ Mg

Suppose,

²⁵ Mg = x

²⁶ Mg = (21.01 - x)%

Then;

avg. atomic mass = \dfrac{78.99}{100 }(23.9850)+\dfrac{x}{100}(24.9858) +\dfrac{21.01-x}{100}(25.9826)

where the avg. atomic mass = 24.3050

∴

24.3050 \times 100 = {78.99}(23.9850)+\dfrac{x}{100}(24.9858) +\dfrac{21.01-x}{100}(25.9826)

2430.5 = 2440.46915 -0.9968 x

0.9968x = 2440.46915 - 2430.5

0.9968x = 9.96915

x  =  9.96915/0.9968

x  =  10.00%

∴ Recall that:

²⁵ Mg = x

²⁶ Mg = (21.01 - x)%

²⁵ Mg = 10.00%

²⁶ Mg = (21.01 - 10.00)%

²⁶ Mg = 11.0%

3 0
3 years ago
Support a scientist doing and experiment in nuclear fusion starts out with twelve atoms how many atoms will most likely results
vlada-n [284]
What context do they ask you?
5 0
3 years ago
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