All categories

3 years ago

In self heating cans, the chemicals in two compartments react with each other and forms……..

Chemistry

2 answers:

irakobra [83]3 years ago

6 0

Quicklime and water

snow_tiger [21]3 years ago

3 0

calcium hydroxide : chemicals are Quicklime and water

You might be interested in

What would barium do to obtain a noble gas structure? gain 2 electrons lose 2 electrons gain 6 electrons lose 6 electrons

Tema [17]

Answer:

Lose two electrons.

Explanation:

Barium is present in group 2.

It is alkaline earth metal.

Its atomic number is 56.

Its electronic configuration is Ba₅₆ = [Xe] 6s².

In order to attain the noble gas electronic configuration it must loses its two valance electrons.

When barium loses it two electron its electronic configuration will equal to the Xenon.

The atomic number of xenon is 54 so barium must loses two electrons to becomes equal to the xenon.

4 0

4 years ago

The highest energy occupied molecular orbital in the f-f bond of the f2 molecule is _____

Morgarella [4.7K]

The basis of finding the answer to this problem is to know the electronic configuration of Fluorine. That would be: [He] 2s² 2p⁵. The valence electrons, which are the outermost electrons of the atom, are the ones that participate in bonding. Since the highest orbital for F is 2p, that means the highest energy occupied would be 2.

3 0

3 years ago

CH3-CH2-CH=CH-CH=CH2

o-na [289]

Answer:

Hydration (of an alkene)

Mechanism : Electrophilic addition.

8 0

3 years ago

A voltaic cell that uses the reaction PdCl2−4(aq)+Cd(s)→Pd(s)+4Cl−(aq)+Cd2+(aq) has a measured standard cell potential of +1.03

Ghella [55]

Answer : The balanced two-half reactions will be,

Oxidation half reaction : $Cd(s)\rightarrow Cd^{2+}(aq)+2e^-$

Reduction half reaction : $Pd^{2+}(aq)+2e^-\rightarrow Pd(s)$

Explanation :

Voltaic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the galvanic cell or electrochemical cell.

In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

The given redox reaction is:

$PdCl_4^{2-}(aq)+Cd(s)\rightarrow Pd(s)+4Cl^-(aq)+Cd^{2+}(aq)$

The balanced two-half reactions will be,

Oxidation half reaction : $Cd(s)\rightarrow Cd^{2+}(aq)+2e^-$

Reduction half reaction : $Pd^{2+}(aq)+2e^-\rightarrow Pd(s)$

7 0

3 years ago

Which line represents the faster moving objec

arsen [322]

Answer:

Explanation:

8 0

3 years ago