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Sever21 [200]
3 years ago
5

Roberto and Genevieve are trying to separate a mixture of beads using a sifter. The chart below shows the colors and sizes of th

e beads. What size must the holes in the sifter be to separate the red and blue beads from the yellow beads?

Physics
2 answers:
spin [16.1K]3 years ago
3 0

Answer:

2.5 mm

Explanation:

It's just big enough for red and blue to fall through but small enough that yellow will stay in

beks73 [17]3 years ago
3 0

Answer:b

Explanation:

Because it look like it

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Which reverses the flow of current through<br> an electric motor?
Gennadij [26K]

Answer:

a commutator

Explanation:

6 0
3 years ago
How many drops of water are in a 1.0 L bottle? (Hint: Start by estimating the diameter of a drop of water.)
o-na [289]

Answer:

N = 2000 drops approx with 1 cm diameter each

Explanation:

Let the diameter of one drop is 1 cm

so volume of one drop is given by

V = \frac{1}{6}\pi d^3

now we have

V = \frac{1}{6}\pi(0.01)^3

V = 0.53 \times 10^{-6} m^3

now in 1L of liquid let say N drops are there

so we have

1L = 10^{-3} m^3

now we have

N = \frac{10^{-3}}{0.53 \times 10^{-6}}

N = 2\times 10^3

so it will have approx 2000 drops in it with diameter 1 cm each drop

7 0
3 years ago
Read 2 more answers
Which statement accurately describes quantum mechanics and nanotechnology?
IgorLugansk [536]

Answer:

Explanation:

edge

6 0
3 years ago
How can we magnetise a piece of iron.
liq [111]
Place the magnet at one end of the piece of metal. The magnet must make as much contact with the metal as possible. Place light pressure on the magnet and rub the metal in one direction only. Magnetization will take some time to accomplish so continue rubbing until the iron or steel attracts other pieces of metal.
4 0
3 years ago
A car and a train move together along straight, parallel paths with the same constant cruising speed v(initial). At t=0 the car
kogti [31]

Answer:

t_1 = \frac{v_i}{a_i}

t_2 = \frac{v_i}{a_i}

Δd = v_it_1 = v_i^2/a_i

Explanation:

As v(t) = v_i + at, when the car is making full stop, v(t_1) = 0 . a = -a_i . Therefore,

0 = v_i - a_it_1\\v_i = a_it_1\\t_1 = \frac{v_i}{a_i}

Apply the same formula above, with v(t_2) = v_i and a = a_i, and the car is starting from 0 speed,  we have

v_i = 0 + a_it_2\\t_2 = \frac{v_i}{a_i}

As s(t) = vt + \frac{at^2}{2}. After t = t_1 + t_2, the car would have traveled a distance of

s(t) = s(t_1) + s(t_2)\\s(t_1) = (v_it_1 - \frac{a_it_1^2}{2})\\ s(t_2) = \frac{a_it_2^2}{2}

Hence s(t) = (v_it_1 - \frac{a_it_1^2}{2}) + \frac{a_it_2^2}{2}

As t_1 = t_2 we can simplify s(t) = v_it_1

After t time, the train would have traveled a distance of s(t) = v_i(t_1 + t_2) = 2v_it_1

Therefore, Δd would be 2v_it_1 - v_it_1 = v_it_1 = v_i^2/a_i

8 0
3 years ago
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