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mojhsa [17]
3 years ago
8

Rewrite the false statements correctly

Physics
1 answer:
FrozenT [24]3 years ago
5 0

Explanation:

1. if an object sjnks in one liquid and floats on another liquid it implies that the density of second liquid is greater than the density of first liquid

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A snowstorm was predicted in Chicago. Identify the possible upper air temperature, surface temperature, and air pressure of Chic
OverLord2011 [107]
The correct answer for this question is this one:

<span>A snowstorm was predicted in Chicago. The possible upper air temperature, surface temperature, and air pressure of Chicago on that day. Normal atmospheric pressure is 29.9 inches of mercury.  </span><em>I'm pretty sure the answer is 40 for upper air, 29 for surface temp, and 30 for air pressure. </em>Hope this helps answer your question and have a nice day ahead.

7 0
3 years ago
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A package is pushed across the floor a distance of 90 feet by exerting a force of 32 lbs downward at an angle of 24 ∘ with the h
Crazy boy [7]

Answer:

2632 foot-pound

Explanation:

Work done: Work is said to be done when ever a force moves a body through a given distance. The S.I unit of force is Newton (N).

From the question,

The expression for work done is given as,

W = Fdcos∅......................... Equation 1

Where W = work done, F = force, d = distance, ∅ = angle between the force and the horizontal.

Given: F = 32 lbs, d = 90 feet, ∅ = 24°

substitute into equation 1

W = 32×90×cos24

W = 2880(0.914)

W = 2632.32

W = 2632 foot-pound

4 0
4 years ago
What does the zeroth law of thermodynamics allow us to define?
NeTakaya
It defines that if two thermodynamic systems are each in equilibrium with a third system, then they are in equilibrium with each other.
3 0
4 years ago
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The horizontal velocity of a projectile when it is in the air is ___.
irga5000 [103]

Answer:

its vi cos thita

Explanation:

3 0
3 years ago
Two slits separated by a distance of d = 0.190 mm are located at a distance of D = 1.91 m from a screen. The screen is oriented
Svetlanka [38]

Answer:

\theta = 0.195^0

Explanation:

wavelength \lambda  = 648 nm \   = 648*10^{-9}m

d = 0.190 mm = 0.190 × 10⁻³ m

D = 1.91 m

By using the formula:

dsin \theta = n \lambda\\\\\theta = sin^{(-1)}(\frac{n \lambda}{d})\\\\\\\theta = sin^{(-1)}(\frac{1*648*10^{-9}}{0.190*10^{-3}})

\theta = 0.195^0

The first maximum will appear at an angle \theta = 0.195^0 from the beam axis

3 0
3 years ago
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