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3 years ago

8

Rewrite the false statements correctly

1 answer:

FrozenT [24]3 years ago

5 0

Explanation:

1. if an object sjnks in one liquid and floats on another liquid it implies that the density of second liquid is greater than the density of first liquid

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What will happen if a car experiences a 300 N force to the right from the engine and a separate 150 N force due to friction and

gayaneshka [121]

Force applied on the car due to engine is given as

$F_1 = 300 N$ towards right

Also there is a force on the car towards left due to air drag

$F_2 = 150 N$ towards left

now the net force on the car will be given as

$\vec F_{net} = \vec F_1 + \vec F_2$

now we can say that since the two forces are here opposite in direction so here the vector sum of two forces will be the algebraic difference of the two forces.

So we can say

$F_{net} = F_1 - F_2$

$F_{net} = 300 - 150$

$F_[net} = 150 N$

So here net force on the car will be 150 N towards right and hence it will accelerate due to same force.

5 0

3 years ago

Which statements about acceleration are true?

bonufazy [111]

It's definitely not B or C. There are things missing from A and D so we can't narrow it down any farther.

4 0

3 years ago

What is potential difference also called?

malfutka [58]

Voltage - V = IR : v= voltage i= current r= resistance

6 0

3 years ago

Find the net charge of a system consisting of 206 electrons and 161 protons. Express your answer using two significant figures.

kondaur [170]

Answer:

-72\times 10^{-19}C[/tex]

Explanation:

Both electron and proton have the same amount of charge but signs are opposite , electron contains negative charge and proton contain positive charge

Charge on 1 electron = $-1.6\times 10^{-19}C$

So charge on 206 electron $=-206\times 1.6\times 10^{-19}C$

Charge on 1 proton = $-1.6\times 10^{-19}C$

So charge on 161 electron $=-106\times 1.6\times 10^{-19}C$

So charge of the system = $(-206+161)\times 1.6\times 10^{-19}C$

$=-72\times 10^{-19}C$

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3 years ago

Dans car has broken down. He decides to push it to a garage 800m away qlong a flat road. He pushes the car with qn average force

Ede4ka [16]

Answer:

Answer = 480000 joule.

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3 0

3 years ago