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vfiekz [6]
3 years ago
7

LEVEL 3

Mathematics
1 answer:
klemol [59]3 years ago
5 0
Maybe adcblhgfe maybe
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What is the solution to 0.25t = 0.25 - t ?
Ede4ka [16]

i think it's t=0.2    Hope it helps:)

8 0
3 years ago
Find the missing side
lisabon 2012 [21]

Answer: 1) The missing length is 40.   2) The missing side is 30 .

Step-by-step explanation:

1)  9^2  + b^2 = 41^2

   81  +  b^2 = 1681

   -81                   -81

   b^2 =  1600

b= 40

2)  24^2 + 18^2 = c^2

 576  + 324 = c^2  

 900 =c^2

c= 30

5 0
3 years ago
Evaluate: 4+8 / 2 x (6 - 3)
slavikrds [6]

Answer:

16

Step-by-step explanation:

4+8/2*(6-3) = 4+8/2*3 = 4+4*3 = 4+12 =16

6 0
3 years ago
Read 2 more answers
Find all the solutions of the equation in the interval [0,2pi). 4sin^(2)x=5-4cosx
gulaghasi [49]
                       4sin²(x) = 5 - 4cos(x)
        4{¹/₂[1 - cos(2x)]} = 5 - 4cos(x)
   4{¹/₂[1] - ¹/₂[cos(2x)]} = 5 - 4cos(x)
         4[¹/₂ - ¹/₂cos(2x)] = 5 - 4cos(x)
     4[¹/₂] - 4[¹/₂cos(2x)] = 5 - 4cos(x)
                2 - 2cos(2x) = 5 - 4cos(x)
              - 2                   - 2
                    -2cos(2x) = 3 - 4cos(x)
            -2[2cos²(x) - 1] = 3 - 4cos(x)
               -4cos²(x) + 2 = 3 - 4cos(x)
                               - 2  - 2
                     -4cos²(x) = 1 - 4cos(x)
-4cos²(x) + 4cos(x) - 1 = 0
 4cos²(x) - 4cos(x) + 1 = 0
               [2cos(x) - 1]² = 0
                  2cos(x) - 1 = 0
                              + 1 + 1
                       2cos(x) = 1
                            2         2
                         cos(x) = ¹/₂
                cos⁻¹[cos(x)] = cos⁻¹(¹/₂)
                                 x = 60, 300
                                 x = π/3, 5π/3

[0, 2π) = 0 ≤ x < 2π
[0, 2π) = 0 ≤ π/3 ≤ 2π or 0 ≤ 5pi/3 < 2π
5 0
3 years ago
hury!!!! Which system is equivalent to StartLayout Enlarged left-brace 1st row y = negative 2 x squared 2nd row y = x minus 2 En
jeka57 [31]

Answer:

3rd Option

Step-by-step explanation:

Which equation is the inverse of y = 7x2 – 10?

y = StartFraction plus-or-minus StartRoot x + 10 EndRoot Over 7 EndFraction

y = plus-or-minus StartRoot StartFraction x + 10 Over 7 EndFraction EndRoot

x = plus-or-minus StartRoot StartFraction x Over 7 EndFraction + 10 EndRoot

y = StartFraction plus-or-minus StartRoot x EndRoot Over 7 EndFraction plus-or-minus StartFraction StartRoot 10 EndRoot Over 7 EndFraction

8 0
3 years ago
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