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Blizzard [7]
3 years ago
11

Jose draws AABC. AB has a length of 10 inches and BC has a length of 15 inches. Determine whether each measurement could be the

length of AC. Choose Yes or No for each measurement. A Yes B No 5. 4 inches 6. 15 inches Yes No 7. 23 inches Yes No 8. 5 inches Yes No​
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer: The length of AC should be between 5 inches and 25 inches

Step-by-step explanation:

Jose in this problem draws a triangle, AABC.

We know the length of two sides of the triangle:

AB = 10 inches

BC = 15 inches

The length of the third side in a generic triangle can be calculated using the cosine theorem: where

a, b, c are the three sides

is the angle opposite to side

Looking at the formula, we observe that:

- The maximum value for  is obtained for , so that . In this case, the length of the missing side  (AC, in this case) is

So, the length of AC must be between 5 and 25 inches.

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baherus [9]
D a rectangle because it has four sides easy for abcd
5 0
3 years ago
Read 2 more answers
What is the volume of sphere of radius 6 m.
Tems11 [23]

Answer:

904.78 m³

Step-by-step explanation:

V = 4/3 × π r³ = 4/3 × π × 6³ = 904.78

8 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
Help Me5k = 6k + 4 - 6
vagabundo [1.1K]

Answer:

k = 2

Step-by-step explanation:

5k = 6k + 4 - 6

We can simplify this by solving 4 - 6 (replacing it with -2 !)

5k = 6k - 2

Now we can subtract 5k from both sides.

0 = k - 2

Finally, we can add 2 to both sides. This gets rid of the negative 2 on the right.

2 = k

Just reversing it...

k = 2

Answer: k = 2

6 0
3 years ago
A student read a 303 –page book in 7 days. The table shows the total number of pages the student had read at the end
DaniilM [7]

To find the average number of pages the student read from day 2 to day 6, add the total pages in these days and divide by 5 days.

<h3>What is the average?</h3>

This is a very common word used in mathematics and stadistics to refer to the mean value in a set of values.

<h3>How to calculate the average from day 2 to day 6?</h3>

Add the pages the person read these days and then divide by 5 (total of days).

For example:

35 + 45 + 10 +25 + 20 = 135 / 5 = 27 pages

Note: This question is incomplete because the table is missing; due to this, the answer is based on general knowledge.

Learn more about average in: brainly.com/question/2426692

7 0
2 years ago
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