When two triangles are similar, they're sides are in proportion.
In order to find the unknown side, we first have to find the ratio of the larger triangle to the smaller triangle.
We can use the sides TV and LN to make the proportion.
= 
The ratio between the two triangles is 21:6
Now we can solve for the unknown side.
= 
Cross multiply:
8 * 21 = 6 * LM
168 = 6LM
Divide both sides by 6:
LM = 28
The unknown side's length is 28 centimeters
Good luck!
Answer:
816 cm²
Step-by-step explanation:
Surface area of the composite figure = (surface area of the larger rectangular prism + surface area of the smaller rectangular prism) - area of the side of the smaller rectangular prism that is joined to the bigger prism.
✔️Surface area of the larger rectangular prism:
Area = L*W*H = 20*5*6 = 600 cm²
✔️surface area of the smaller rectangular prism:
Area = L*W*H = 12*4*6 = 288 cm²
✔️area of the side of the smaller rectangular prism that is joined to the bigger prism.
Area = L*W = 12*6 = 72 cm²
Surface area of the composite = (600 + 288) - 72 = 888 - 72 = 816 cm².
The solution to the equation is x = 4
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient
<h3>How to determine the solution to the system?</h3>
A system of linear equations is a collection of at least two linear equations.
In this case, the equation is given as
(x + 20)/2 = 3x
Multiply both sides of the equation by 2
x + 20 = 6x
Subtract x from both sides of the equation
5x = 20
Divide both sides of the equation by 5
x = 4
hence, the solution to the equation is x = 4
Read more about equations at:
brainly.com/question/2972832
#SPJ1
200.96 rounded to the nearest hundredths would be 201 because in you decimal places you have .96 and your thousandths place is 6 so you would round. Up the 9 to 10 so you would have to make 200 into 201 therefore your answer would be 201
Answer:
No, because the reflection of ABC is not congruent to A’B’C’.
Step-by-step explanation:
we know that
The rule of the reflection across the line y=x is equal to
(x,y) -------> (y,x)
so
A(-6,6) -------> A'(6,-6) ----> is ok
B(-3,3) ------> B'(3,-3) ----> is ok
C(-8,2) ------> C'(8,-2) ----> is not ok ( is not a reflection acros the line y=x)
therefore
The triangles are no t congruent, because the reflection of ABC is not congruent to A’B’C’
