First, we must find the equation of the given line. The slope is "rise over run," or the change in y over the change in x from one point to another. The two points shown are (0,-1) and (3,1). In these points, y increases by 2. This means the change in y is 2. In these points, x increase by 3. This means the change in x is 3. Thus, the change in y over change in x is 2/3. This means that the slop of the given line is 2/3.
In the form y=mx+b, where m is the slope, b is the y intercept. This is because the y intercept occurs when x is 0. If x is zero, mx is zero, so y=b. In other words, when x equals 0, y=b. This creates the point (0,b), which is the y-intercept. Since the y-intercept of the given line is -3, the equation for this line is: y=2/3x-3.
A line parallel to this will need to have the same slope. This allows us to eliminate choices C and D, which do not have the same slope.
In order for the line to have an x-intercept of (-3,0), y must equal 0 when x is -3, since ordered pairs are (x,y). We can solve the equation using the information we know: 0=((2/3)(-3))+b This is because we know the slope is 2/3, and that when x is -3, y is 0.
Then, we can solve from there: 0=(-2)+b (just multiply 2/3 and -3) 2=b (add 2 to both sides)
substitute equation 2 and equation 4 in equation 1 x+[14x/25]+[12x/25]=170------> multiply by 25 both sides 25x+14x+12x=4250 51x=4250 x=4250/51 x=250/3 y=14x/25------> y=(250/3)*(14/25)----> y=140/3 z=12y/14-----> (140/3)*12/14----> z=40
Using Heron's formula, Area of the triangle = √s (s-a) (s-b) (s-c) where s is the semiperimeter s=170/2-----> s=85 ft Area=√85*[85-250/3]*[85-140/3]*[85-40] Area=9.22*[1.67]*[38.33]*[45]------> Area=26558.21 ft²
The second equation is <span>-5-2y=2, then </span> <span>-2y=2-(-5), </span> -2y=2+5, -2y=7, y=7÷(-2), y=-3.5. The first equation is 2x+5y=16, subtitude y=-3.5 in this equation, then 2x+5·(-3.5)=16, 2x-17.5=16, 2x=16-(-17.5), 2x=16+17.5, 2x=33.5, x=33.5÷2, x=16.75. Answer: (16.75,-3.5)
