If the heat of fusion of water is 3.4 × 10^2 joule/gram, the heat energy amount required to change 15.0 grams of ice at 0°c to 15.0 grams of water at 0°c is 5100 joule (5100 = 3.4 x 10^2 x 15).
The problem above can be solved by using the heat of fusion formula. The formula for calculating the heat of fusion described as C = q/m, where: C is the heat of fusion, q is the amount of heat energy required, and m is the mass of the object.
Answer:
<u>AZ₂</u>
Explanation:
The formed compound will not contain Q because mass percentages, %A and %B, form 100% of the compound.
<u>Steps</u>
- Change % of each element into grams.
- Convert grams of each element into moles by dividing grams by molar mass.
- Divide all moles by the smallest number of moles.
- If the moles are all whole numbers, then you’re done and that’s your empirical formula.
- If not, multiply all moles by number such that everything is a whole number.
<u>Solving</u>
- We have 15.66g of A and 84.34g of Z
- Moles of A, n(A) = 15.66/15.45 = 1.01 moles
- Moles of Z, n(Z) = 84.34/41.62 = 2.02 moles
- A = 1.01/1.01 = 1 and Z = 2.02/1.01 = 2
- Therefore, the empirical formula is <u>AZ₂</u>
