**$ 2000 is invested at 3 % interest and $ 4000 is invested at 8 % interest**

<em><u>**Solution:**</u></em>

Given that, total of $6000 was invested

**Let "x" be the amount invested at 3 % interest**

**Then, (6000 - x) is the amount invested at 8 % interest**

Given that,

<em><u>**The total yearly interest amounted to $380**</u></em>

Then, we can frame a equation as:

<em><u>**Solve the above expression for "x"**</u></em>

Thus,** $ 2000 is invested at 3 % interest**

(6000 - x) = 6000 - 2000 = 4000

**$ 4000 is invested at 8 % interest**