<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
<h2><u>
PLEASE MARK BRAINLIEST!</u></h2>
Answer:
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<h3>
Answer: Solution is x = -2</h3>
You have two equations with y1 = f(x) and y2 = g(x).
We're looking for the values of x such that f(x) = g(x). This is the same as trying to solve y1 = y2.
The first row of the table shows y1 and y2 having the same value 5. So we just record the x value that goes with these y values.
Answer:
each boy ate 8 cookies
Step-by-step explanation:
48-16=32
32 divided by 4=8
so each of them ate 8 cookies
Answer:
C. 8.52624...
Step-by-step explanation:
The reason that C is different is because all of the other decimals are terminating decimals (meaning that they end or stop), while C is a repeating decimal, because it never ends.
