we have been given that in ΔFGH, the measure of ∠H=90°, GF = 53, HG = 28, and FH = 45. We are asked to find the ratio that represents the sine of ∠G.
First of all, we will draw a right triangle using our given information.
We know that sine relates opposite side of right triangle with hypotenuse.
We can see from the attachment that opposite side to angle G is FH and hypotenuse is GF.
Therefore, the ratio 
represents the sine of ∠G.
Answer:
The slope is 3/5.
Step-by-step explanation:
I am assuming you mean
10x + 6y = 84
6y = -10x + 84
y = -5/3 x + 14.
So the slope of this line is -5/3 and the slope of a line perpendicular to it is
-1 / -5/3 = 3/5.
Answer: i think it should be 1:3=2:6
Step-by-step explanation:
You can see that angle TQV = 90 degrees
Angle RQV = 136 degrees
Angles RQV and UQV are supplementary and equal 180 degrees since they form a straight line. Therefore angle UQV = 180 - 136 = 44 degrees.
TQU + UQV = 90 degrees. Therefore, TQU = 90 - UQV.
90 - 44 = 46 degrees for angle TQU.
Answer:
The equation
Step-by-step explanation:
It should be 0.20 per topping not 0.25
hope this helps
