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choli [55]
3 years ago
15

2 [ 32 - (4-1) to the third power ]

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
6 0

Answer:

The correct answer is 10 hope this helps can u pls give me brainliest

Step-by-step explanation:

Tems11 [23]3 years ago
4 0

Answer:

Step-by-step explanation:

2

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Help [(0.3×8)+(1.5×3)]+36
Vaselesa [24]
0.3×8=2.4
1.5×3=4.5

(2.4+4.5)+36=42.9
6 0
3 years ago
The width of a room is 60% of the land is 10 feet what is the area of the room
nikdorinn [45]
I believe it is 600.

8 0
3 years ago
PLS HELP ME I WILL MARK YOU AS BRAINLIEST!!!
natali 33 [55]

Answer:

Option B, 187.5 cm³

Step-by-step explanation:

Volume of the triangular prism,

base area × height

= (10×7.5/2)×5

= 187.5 cm³

4 0
3 years ago
Find x. Round your answer to the nearest tenth of a degree.
viktelen [127]

Answer: x=52.6°

Step-by-step explanation:

To find the value of x, we have to use our SOHCAHTOA. We can eliminate sine and cosine because both uses hypotenuse, which is not labelled. Therefore, we use tangent.

tan(x)=\frac{17}{13}

To find x, we want to use inverse tangent.

x=tan^{-1}(\frac{17}{13} )      [plug into calculator]

x=52.6

Now, we know that x=52.6°.

3 0
3 years ago
Show that ∆ABC is a right triangle if A(0, 0), B(3, 2), and C(–2, 3). Find the slope m1 of AB and the slope m2 of AC and verify
Mariana [72]

First we'll show this is a right triangle by the Pythagorean Theorem:

A(0,0), B(3,2), C(-2, 3)

AB^2=3^2+2^2=13

AC^2=(-2)^2+3^2=13

BC^2 = (-3 -3)^2 + (3 -2)^2 = 26

Since AB^2+AC^2=BC^2 we have a right triangle, by the (converse to the) Pythagorean Theorem.  We also see it's isosceles, AB=AC.

\textrm{Slope of AB} = m_1 = \dfrac{2 - 0}{3 - 0} = \dfrac 2 3

\textrm{Slope of AC} = m_2 = \dfrac{3 - 0}{-2 - 0} = -\dfrac 3 2

m_1 m_2 = (\frac 2 3)(-\frac 3 2 ) = -1 \quad\checkmark  

That's the end of the homework but I'll go on a bit.

Another way to show perpendicularity, essentially the same as the other two, is by a zero as the dot product of the sides as vectors, differences between vertices.

Vector AB = B - A = (3,2)

Vector AC = C - A = (-2, 3)

AB · AC = 3(-2) + 2(3) = 0

A zero dot product means

AB ⊥ AC

8 0
3 years ago
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