Answer:
3,2
Step-by-step explanation:
If it has a constant slope that means it makes a straight line making it linear
1. -9 need to multiple to both number
-9 X n= -9n -9 X -3 = 21
-9n + 21
2. -10 X 9n = -90n -10 X 3 = -30
-90n - 30 - 8
-90n - 38
Hope that helps
Answer:
Step-by-step explanation:
Hello!
a.
Given the data corresponding the variables:
x 2 6 6 7 9
y 3 2 6 9 5
The Scatterplot is attached.
b.
To compute the correlation coefficient you need several auxiliary calculations:
∑X= 30
∑X²= 206
∑Y= 25
∑Y²= 155
∑XY= 162
![r= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{\sqrt{[sumX^2-\frac{(sumX)^2}{n} ][sumY^2-\frac{(sumY)^2}{n} ]} }](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7BsumXY-%5Cfrac%7B%28sumX%29%28sumY%29%7D%7Bn%7D%20%7D%7B%5Csqrt%7B%5BsumX%5E2-%5Cfrac%7B%28sumX%29%5E2%7D%7Bn%7D%20%5D%5BsumY%5E2-%5Cfrac%7B%28sumY%29%5E2%7D%7Bn%7D%20%5D%7D%20%7D)
![r= \frac{162-\frac{(30)*(25)}{5} }{\sqrt{[206-\frac{(30)^2}{5} ][155-\frac{(25)^2}{5} ]} }](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B162-%5Cfrac%7B%2830%29%2A%2825%29%7D%7B5%7D%20%7D%7B%5Csqrt%7B%5B206-%5Cfrac%7B%2830%29%5E2%7D%7B5%7D%20%5D%5B155-%5Cfrac%7B%2825%29%5E2%7D%7B5%7D%20%5D%7D%20%7D)
r= 0.429 ≅ 0.43
c.
The critical value for r has n-2 degrees of freedom, let's say for example you have α:0.05

For a two-tailed test.
Because the correlation coefficient is <u>positive</u> and the absolute value of the correlation coefficient, _<u>0.43</u>___, is <u>not greater</u> than the critical value for this data set,_<u>0.878</u>__, <u>no </u>linear relationship exists between x and y.
I hope it helps!