Could someone please tell me or explain how to solve these types of equations?? you don’t have to do these problems specifically
, but just tell me how to do it
also sorry for the bad quality,,,
also sorry for the bad quality,,,
1 answer:
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Answer:
B. 10
Step-by-step explanation:
First, we need to recognize that the two triangles are similar (the triangle with a leg value of 21 and the triangle with a leg value of 4 and hypotenuse x)
Let's first label the leg of the second triangle as y.
Then, we can set up this equation
Cross multiplying gives us
84=y^2
So, y=sqrt(84) or 2 sqrt(21).
Now, using the pythagorean theorem, we get
4^2+2sqrt(21)^2=x^2
100=x^2
x=10