All categories

3 years ago

What is the magnetic field a distance 0.03 m away from a long, straight wire carrying a current of 4.4 A?

Physics

1 answer:

TiliK225 [7]3 years ago

7 0

Answer:

B = 2.93 x 10⁻⁵ T

Explanation:

The magnetic field due to a straight long wire carrying a current can be found by using Biot-Savart Law, as follows:

B = μ₀I/2πr

where,

B = Magnitude of the magnetic Field = ?

μ₀ = Permeability of free space = 4π x 10⁻⁷ Tm/A

r = distance from wire = 0.03 m

I = Current = 4.4 A

Therefore,

B = (4π x 10⁻⁷ Tm/A)(4.4 A)/(2π)(0.03 m)

You might be interested in

If you apply the same amount of force to a box with 25 g of mass and a box 200 g which will have a greater acceleration and why?

astraxan [27]

25g becoz acceleration is inversely to the mass when force is constant

3 0

4 years ago

2. A man in a hot air balloon drops his “five guy's hamburger” over the edge of the basket. The

disa [49]

Answer:

19.3 m/s

Explanation:

Considering that no initial velocity was imparted to the hamburger, then we can use the distance covered formula for motion under constant acceleration (that of gravity) and solve for the time it took to reach the ground.

D = vi * t + (1/2) a * t^2

in our case

19 = 0 + 4.9 t^2

t^2 = 19/4.9

then t is approximately 1.97 seconds

We now use this time information in the equation for velocity under accelerated motion (due to gravity)

Vf = Vi + g * t

For our case:

Vf = 0 + 9.8 * 1.97 = 19.3 m/s

5 0

3 years ago

Help ASAP plsssss:///

kenny6666 [7]

Answer:

Explanation:

8 0

3 years ago

Your film idea is about drones that take over the world. In the script, two drones are flying horizontally at the same speed and

Stella [2.4K]

Answer:

vₓ = 20 m/s, v_{y} = -15 m / s

Explanation:

This is a conservation of moment problem, since it is a vector quantity we can work each axis independently

The system is formed by the two drones, so the forces during the crash are internal and the moment is conserved

X axis

Initial moment. Before the crash

p₀ = m₁ v₀ₓ + m₂ v₀ₓ

Final moment. After the crash

p_{fx} = (m₁ + m₂) vₓ

p₀ₓ = $p_{fx}$

m₁ v₀ₓ + m₂ v₀ₓ = (m₁ + m₂) vₓ

vₓ = (m₁ + m₂) v₀ₓ / (m₁ + m₂)

vₓ = v₀ₓ = 20 m/s

Y Axis

Initial

p_{oy} = m₁ v_{oy}

Final

p_{fy} = (m₁ + m₂) v_{y}

p_{oy} = p_{fy}

the drom rises and when it falls it has the same speed because there is no friction v_{oy} = -60 m/s

m₁ $v_{oy}$ = (m₁ + m₂) v_{y}

v_{y} = m₁ / (m₁ + m₂) v_{oy}

v_{y} = 1/4 60

v_{y} = -15 m / s

Vertical speed is down

5 0

4 years ago

What will be the fundamental frequency and first three overtones for a 26cm long organ at 20°C if it is open ( at 20°C, the spee

kakasveta [241]

Explanation:

The frequency of an organ pipe if it is open is given by :

$f=\dfrac{nv}{2l}$

v is speed of sound in air is 343 m/s at 20°C

For fundamental frequency, n = 1

$f=\dfrac{1\times 343}{2\times 0.26}\\\\f=659.61\ Hz$

First overtone frequency,

$f_1=2f\\\\f_1=2\times 659.61\\\\f_1=1319.22\ Hz$

Second overtone frequency,

$f_2=3f\\\\f_2=3\times 659.61\\\\f_2=1978.83\ Hz$

Third overtone frequency

$f_3=4f\\\\f_3=4\times 659.61\\\\f_3=2638.44\ Hz$

Hence, this is the required solution.

3 0

3 years ago