d = distance = 0.76 m <span>
<span>a = acceleration due to gravity = 9.81 m/s^2</span>
u = initial velocity = 0 (as the ball rolls off the table the
vertical velocity = 0
t = time = missing so we need to solve it
So we use the equation d = ut + 1/2 at², and ever since u is
zero, ut is zero and the equation becomes to d = 1/2 at² and this reorders to t
= sqrt (2d/a) = 0.39 seconds.
Since there are no forces performing in the horizontal
direction, this means that there is no acceleration in the horizontal direction
and consequently the horizontal velocity is persistent. </span>
Velocity = distance/
time.
Horizontal velocity is
therefore horizontal distance/time = 0.61 m/0.39s = 1.56 m/s.
<span> </span>
The answer is : <span>Gravity draws an object towards its strongest point. The main things holding you back are air resistance and friction. As a hill gets steeper, you are more in line with the center of gravity, so it overcomes friction and you move faster. Eventually when you are moving vertically there is no friction other than air resistance itself. At this time you will accelerate at 32 feet per second every second until you either hit something or reach terminal velocity which is around 120 mph. Air resistance (on the Earth at least) will not allow you to travel any faster. Hope this Helped! Good Luck! :)</span>
<em>Hey There!!</em>
<em>I think the answer is:</em>
<em>B). </em><em>Mars has less mass than Earth. </em>
Explanation:
<em>Because, due to the law of gravity, or gravitation, by which all things with mass around the planet Mars are brought towards it. It is weaker than Earth's gravity due to the planet's smaller mass.</em>
<em>P.S </em><em>Tell me if this is wrong....</em>
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<em>#</em>
<em> </em>
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<em># </em>
<em> </em>
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<em>(^∀^●)ノシ</em>
The answer is (C)= zero but that it is swirling rapidly in all directions.
Answer:
The applied torque is 3.84 N-m.
Explanation:
Given that,
Moment of inertia of the wheel is 
Initial speed of the wheel is 0 (at rest)
Final angular speed is 25 rad/s
Time, t = 13 s
The relation between moment of inertia and torque is given by :

So, the applied torque is 3.84 N-m.