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diamong [38]
4 years ago
12

Which of these statements best explains why the size of the refracting telescope lens is kept small at the cost of reducing its

capacity to gather radiations from space?
•Big telescopes are more portable.
•Big lenses gather harmful radiations from space.
•Big lenses do not focus light properly to produce clear images.
•Big telescopes are not reliable enough to be used for research.
Physics
2 answers:
mina [271]4 years ago
8 0
Among the choices the <span>statements that best explains why the size of the refracting telescope lens is kept small at the cost of reducing its capacity to gather radiations from space is "</span><span>Big lenses do not focus light properly to produce clear images. "</span>
PtichkaEL [24]4 years ago
7 0

Answer : Big lenses do not focus light properly to produce clear images.

Explanation :

A telescope that uses a combination of mirrors which is used to reflect light and forms an image.

The first reflecting telescope was invented by Newton in 1668. The size of the refracting telescope lens is kept small at the cost of reducing its capacity to gather radiations from space.

The correct option is (c) " Big lenses do not focus light properly to produce clear images ".

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An autographed baseball rolls off of a 0.76 m high desk and strikes the floor 0.61 m away from the desk. how fast was it rolling
zmey [24]

d = distance = 0.76 m <span>
<span>a = acceleration due to gravity = 9.81 m/s^2</span>
u = initial velocity = 0 (as the ball rolls off the table the vertical velocity = 0 
t = time = missing so we need to solve it 

So we use the equation d = ut + 1/2 at², and ever since u is zero, ut is zero and the equation becomes to d = 1/2 at² and this reorders to t = sqrt (2d/a) = 0.39 seconds. 

Since there are no forces performing in the horizontal direction, this means that there is no acceleration in the horizontal direction and consequently the horizontal velocity is persistent. </span>

Velocity = distance/ time.

Horizontal velocity is therefore horizontal distance/time = 0.61 m/0.39s = 1.56 m/s.

<span> </span>

8 0
4 years ago
Why does an object roll faster down a steeper hill than a not so steep hill.
Natasha2012 [34]
 The answer is : <span>Gravity draws an object towards its strongest point. The main things holding you back are air resistance and friction. As a hill gets steeper, you are more in line with the center of gravity, so it overcomes friction and you move faster. Eventually when you are moving vertically there is no friction other than air resistance itself. At this time you will accelerate at 32 feet per second every second until you either hit something or reach terminal velocity which is around 120 mph. Air resistance (on the Earth at least) will not allow you to travel any faster. Hope this Helped! Good Luck! :)</span>
3 0
3 years ago
Why is the gravity on Earth greater than the gravity on Mars? (HELP will mark as Brainliest!!!)
steposvetlana [31]

<em>Hey There!!</em>

<em>I think the answer is:</em>

<em>B). </em><em>Mars has less mass than Earth. </em>

Explanation:

<em>Because, due to the law of gravity, or gravitation, by which all things with mass around the planet Mars are brought towards it. It is weaker than Earth's gravity due to the planet's smaller mass.</em>

<em>P.S </em><em>Tell me if this is wrong....</em>

<em />GoodLuck!!<em />

<em>#</em>Be<em> </em>Bold<em />

<em># </em>Always<em> </em>Brainly!<em />

<em>(^∀^●)ノシ</em>

3 0
4 years ago
Read 2 more answers
You are out for a bicycle ride on a calm, windless day. You are heading northward on a level road and are experiencing a pressur
goldenfox [79]
The answer is (C)= zero but that it is swirling rapidly in all directions.
8 0
3 years ago
A constant torque is applied to a rigid wheel whose moment of inertia is 2.0 kg · m2 around the axis of rotation. If the wheel s
Jlenok [28]

Answer:

The applied torque is 3.84 N-m.      

Explanation:

Given that,

Moment of inertia of the wheel is 2\ kg-m^2

Initial speed of the wheel is 0 (at rest)

Final angular speed is 25 rad/s

Time, t = 13 s

The relation between moment of inertia and torque is given by :

\tau=I\alpha \\\\\tau=I\times \dfrac{\omega_f}{t}\\\\\tau=2\times \dfrac{25}{13}\\\\\tau=+3.84\ N-m

So, the applied torque is 3.84 N-m.

4 0
3 years ago
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