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Veronika [31]
3 years ago
9

A space station has a mass M and orbits Earth in a circular orbit at a height above Earth’s surface. An astronaut in the space s

tation appears weightless because the astronaut seems to float. Which of the following claims is true about the force exerted on the astronaut by Earth ?
A) there is no force exerted on the astronaut by Earth because the astronaut is 400km above Earth’s surface

B) the force exerted on the astronaut by Earth is less than the force exerted by the astronaut because the astronaut is 400km above Earths surface

C) the force exerted on the astronaut by Earth is equal to the gravitational force of the space station that is exerted on the astronaut; the two equal forces balance to cause the astronaut to float.

D) the force exerted on the astronaut by Earth is equal to the force exerted on Earth by the astronaut

Please help me with this question if you can ! It would be very much appreciated . Thank you
Physics
1 answer:
Svetllana [295]3 years ago
8 0

Answer:

The correct option is;

D) The force exerted on the astronaut by Earth is equal to the force exerted on Earth by the astronaut

Explanation:

According to Newton's third law of motion, in nature, for every action, there is an equal and opposite reaction, such that if a first object exerts a certain amount of force on a second object, the second object will exert a force of equal magnitude and opposite direction to that exerted by the first object

Therefore, the gravitational force exerted by Earth on the astronaut, is equal to the force exerted by the astronaut on Earth.

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You charge an initially uncharged 65.7-mf capacitor through a 39.1-Ï resistor by means of a 9.00-v battery having negligible int
uysha [10]
In a RC-circuit, with the capacitor initially uncharged,  when we connect the battery to the circuit the charge on the capacitor starts to increase following the law:
Q(t) = Q_0 (1-e^{-t/\tau})
where t is the time, Q_0 = CV is the maximum charge on the capacitor at voltage V, and \tau = RC is the time constant of the circuit.
Using this law, we can answer all the three questions of the problem.

1) Using R=39.1 \Omega and C= 65.7 mF=65.7\cdot 10^{-3}F, the time constant of the circuit is:
\tau = RC=(39.1 \Omega)(65.7 \cdot 10^{-3}F)=2.57 s

2) To find the charge on the capacitor at time t=1.95 \tau, we must find before the maximum charge on the capacitor, which is
Q_0 = CV=(65.7 \cdot 10^{-3}F)(9 V)=0.59 C
And then, the charge at time t=1.95 \tau is equal to
Q(1.95 \tau) = Q_0 (1-e^{-t/\tau})=(0.59 C)(1-e^{-1.95})=0.51 C

3) After a long time (let's say much larger than the time constant of the circuit), the capacitor will be fully charged, this means its charge will be Q_0 = 0.59 C. We can see this also from the previous formule, by using t=\infty:
Q(t) = Q_0 (1-e^{-\infty})=Q_0(1-0) = 0.59 C

4 0
3 years ago
What invisible force will cause you to fall to the earth if you fall off your bed?
Katyanochek1 [597]

Answer:

The answer to this is falling all the way through the Earth is impossible, since its core is molten. ... As you approached the center of the earth the pull of gravity would decline and eventually (at the center) cease, but inertia would keep you going.

Explanation:

your welcome

8 0
3 years ago
How long does it take for 4 coulombs of charge to pass through a cross
Galina-37 [17]

Answer: 2 seconds

Explanation:

Given that,

Time (T) = ?

Charge (Q) = 4 coulombs

current (I) = 2 Amps

Since charge depends on the amount of current flowing through the wire in a given time, hence

Charge = Current x Time

Q = IT

4 coulombs = 2 Amps x Time

Time = 4 coulombs / 2 Amps

Time = 2 seconds

Thus, it takes 2 seconds for the current to flow through the wire

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3 years ago
A man pushes on a trunk with a force of 250 newtons. The trunk does not move. How much positive work is done on the trunk?
Digiron [165]

Answer:

F is 250 N

d is 0 m

F x d

=250 x 0

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The answer is 0.0 J.

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3 years ago
Problem:
Mars2501 [29]
I do have a couple ideas and tips that may help you win. I don’t know how the guidelines are set up so if the ideas won’t be helpful I apologize.

First off put some ice cubes in the container then sprinkle salt on them, The reaction will create an effect and be super cold.


Another idea would be to get some dry ice if you able to, This will freeze it solid within seconds.


The last idea combines the the first. Take a bowl and fill it with with water and ice (Make sure the bowl is insulated) add a small handful of salt into the bowl, Put your drink into the cooler and before shutting stir then well then close and wait for the amount of time left, Your should have a cold water bottle.


I hoped this helped you out and I hope you also win the contest.
8 0
3 years ago
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