Normal force is mass x gravity, so mass x 9.81
( 1.05 x 10¹⁵ km ) x ( 1 LY / 9.5 x 10¹² km ) x ( 1 psc / 3.262 LY ) =
(1.05) / (9.5 x 3.262) x (km · LY · psc) / (km · LY) x (10¹⁵⁻¹²) =
(0.03388) x (psc) x (10³) =
33.88 parsecs
Answer:


Explanation:
The statement is described physically by means of the Principle of Momentum Conservation. Let assume that first person moves in the positive direction:
First Person

Second Person

The final velocities of the two people after the snowball is exchanged is:


Explanation:
The given data is as follows.
Length of beam, (L) = 5.50 m
Weight of the beam, (
) = 332 N
Weight of the Suki, (
) = 505 N
After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.

= 0
x = 
= 
= 0.986 m
Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.
Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.
Answer:
450 joules ; 450 joules ; 45.9 m
Explanation:
Given that :
Initial Velocity, u = 30m/s
Mass, m = 1 kg
Kinetic Energy of ball (KE) = 0.5mu²
K. E = 0.5 * 1 * 30^2
K.E = 0.5 * 900
K.E = 450 Joules
B.) Potential Energy (P. E)
P. E = mgh
At the highest point, all kinetic energy has would have become potential energy, hence
K. E = P. E = 450 Joules
C) Height of the ball :
From ; P. E = mgh
Where ; g = acceleration due to gravity = 9.8m/s² ; h = height
450 = 1 * 9.8 * h
450 = 9.8h
h = 450 / 9.8
h = 45.918
h = 45.9 m