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faust18 [17]
3 years ago
5

Please help asap! The numbers for the graph have to be whole! (Can’t be .5)

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0
Put the top point on the first point from the top and the other one on the first point from the bottom.

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Simplify this expression:<br> -(x+2)+4<br><br> i have no idea im not good with math ;(
topjm [15]

ANSWER :

- ( x+ 2 ) + 4

-x - 2 + 4

-x + 2

8 0
3 years ago
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How would I get a answer?
tresset_1 [31]

Answer:

0.07kg

Step-by-step explanation:

1kg = 1000g

so grams/1000 =kg

70/1000 = 0.07kg

3 0
2 years ago
Answer ASAP:
Irina-Kira [14]

Answer:

To order fractions from least to greatest, start by finding the lowest common denominator for all of the fractions. Next, convert each of the fractions by dividing the lowest common denominator by the denominator and then multiplying the top and bottom of the fraction by your answer.

Step-by-step explanation:

Hope this helps ❤️

5 0
3 years ago
What is the solution to the following system?<br> x+y+z=6 <br> x-y+z=8 <br> x+y-z=0
Ghella [55]
I don't really know if this is correct but I think it is x+y+z=14
4 0
3 years ago
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Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a
Vikki [24]

Answer:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

Step-by-step explanation:

Information given:

n=131 represent the sample size

\hat p=0.81 represent the estimated proportion

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.326

And replacing into the confidence interval formula we got:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

6 0
3 years ago
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