Answer:
12x³+89x²-261x (?)
Step-by-step explanation:
For this equation, I am going to assume you want to find the value of the expression and you're multiplying all the values (since you can't find the value of x with this unless you had an equation).
(x)(4x-9)(3x+29)
(4x²-9x)(3x+29)
12x³+89x²-261x
If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
the length of the bottom side is 17-3 = 10
to be a square all sides need to be 10 units.
A(7,13)
B (17,13)
So first you need to open the brackets, so it would be x+2+4x-122=180. Then we can add the 4x and the other x to make 5x, and then by doing 2-122 we get -120. This gives us the equation 5x-120=180. We then isolate the variable by moving the -120 to the other side of the equation and becoming a positive, so it would look like 5x=180+120. Then, we have 5x=300. 300 divides by 5 is 60 making X=60. Hope this helps!
Answer:
No
Step-by-step explanation:
No function, because the same output can't have two different inputs.
