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Likurg_2 [28]
3 years ago
12

How high (in meters) can a 40 N force move a load, when 395 J of work is done? (round to the nearest 10th)

Physics
1 answer:
alex41 [277]3 years ago
7 0

Answer:

9.9 m

Explanation:

From the question given above, the following data were obtained:

Force (F) = 40 N

Workdone (Wd) = 395 J

Height (h) =?

The height can be obtained as follow:

Potential energy = mgh = Fh

395 = 40 × h

Divide both side by 40

h = 395 / 40

h = 9.9 m

Thus, the height is 9.9 m.

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