The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.
<h3>How to determine the friction factor</h3>
Using the formula
μ = viscosity = 0. 06 Pas
d = diameter = 120mm = 0. 12m
V = velocity = 1m/s and 3m/s
ρ = density = 0.9
a. Velocity = 1m/s
friction factor = 0. 52 × 
friction factor = 0. 52 × 
friction factor = 0. 52 × 0. 55
friction factor 
b. When V = 3mls
Friction factor = 0. 52 × 
Friction factor = 0. 52 × 
Friction factor = 0. 52 × 0. 185
Friction factor 
Loss When V = 1m/s
Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter
Head loss = 0. 289 ×
×
× 
Head loss = 1. 80 × 10^8
Head loss When V = 3m/s
Head loss =
×
×
× 
Head loss = 5. 3× 10^8
Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.
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The correct answer is A: equal protection.
Further Explanation:
The fourteenth amendment was integral in granting equal rights to all citizens of the United States. This was not only for the citizens born in the country but naturalized citizens, former/freed slaves, and all children born to people not naturalized Americans.
The fourteenth amendment timeline is listed below;
- 06-08-1866 - By a vote of 33-11 the fourteenth amendment passed the Senate.
- 06-13-1866 - By a vote of 120-32 the fourteenth amendment passed the House of Representatives.
- 06-18-1866 - United States Statutes at Large, entered the amendment into text.
- 06-22-1866 - President Andrew Jackson announced that the the amendment was sent to be ratified by the states.
- 07-28-1868 - A proclamation stating the ratification was certified.
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It can be transferred by I, II, and III
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False , because collinear points lie on a line not on a plane.
Coplanar points on the other hand, lie on a plane.
From Hooke's law, the length of the spring after extension and after the mass is attached is 1.788 meters. Option B is the answer.
<h3>
HOOKE'S LAW</h3>
Hooke's law state that in an elastic material, the force applied is directly proportional to the extension provided that the elastic limit is not exceeded.
Given that a 12.0 kg mass is attached to 1.2 m long spring with a spring constant of 200.0 N/m.
The given parameters are:
- Initial length
= 1.2 m
- Spring constant K = 200 N/m
According to Hooke's law
F = Ke
But F = mg
mg = Ke
Substitute all the parameters into the formula to get extension e
12 x 9.8 = 200e
e = 117.6 / 200
e = 0.588 m
The length of the spring after extension and after the mass is attached will be
=
+ e
= 1.2 + 0.588
= 1.788 m
Therefore, the correct answer is option B because the length of the spring after extension and after the mass is attached is 1.788 meters.
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