What is the heat extracted from the cold reservoir for the refrigerator shown in(Figure 1) ? Assume that W1 = -123J and W2 = 88J .

Qc= _________ 

Part B

K=105J

7 0

3 years ago

Questions E6 a& b and E7 a&b?

erica [24]

Explanation:

6a) Work = force × distance

W = Fd

W = (60 N) (10 m)

W = 600 J

6b) Change in energy = work

ΔKE = 600 J

7a) Kinetic energy is half the mass times the square of the velocity.

KE = ½ mv²

KE = ½ (0.4 kg) (25 m/s)²

KE = 125 J

7b) Work = change in energy. When the ball is stopped, it has zero kinetic energy.

W = ΔKE

W = 0 J − 125 J

W = -125 J

8 0

3 years ago

2. What are the 3 types of matter?

Lapatulllka [165]

Answer:

the three types of matter are solid, liquid, gas

8 0

2 years ago

a transformer changes 95 v acorss the primary to 875 V acorss the secondary. If the primmary coil has 450 turns how many turns d

natita [175]

Answer:

The number of turns in the secondary coil is 4145 turns

Explanation:

Given;

the induced emf on the primary coil, $E_p$ = 95 V

the induced emf on the secondary coil, $E_s$ = 875 V

the number of turns in the primary coil, $N_p$ = 450 turns

the number of turns in the secondary coil, $N_s$ = ?

The number of turns in the secondary coil is calculated as;

$\frac{N_p}{N_s} = \frac{E_p}{E_s}$

$N_s = \frac{N_pE_s}{E_p} \\\\N_s = \frac{450*875}{95} \\\\N_s = 4145 \ turns$

Therefore, the number of turns in the secondary coil is 4145 turns.

8 0

3 years ago