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anyanavicka [17]
3 years ago
5

A 3 kilogram cat is resting on top of a bookshelf that is 1 meters high. What is the cat’s gravitational potential energy relati

ve to the floor?
Physics
1 answer:
AVprozaik [17]3 years ago
6 0

We have: Gravitational Potential Energy (U) = mgh

Here, m = 3 Kg

g = 9.8 m/s²        [ constant value for earth system ]

h = 3 m


Substitute their values into the expression:

U = 3 × 9.8 × 3

U = 88.2 J


In short, Your Answer would be 88.2 Joules


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A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 780 N on him. The
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Answer:

f = 556.4 N

Explanation:

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A closed box is filled with dry ice at a temperature of -87.1°C, while the outside temperature is 17.6°C. The box is cubical, me
natta225 [31]

Answer:

K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹

Explanation:

Rate of flow of heat through a material is given by the following expression

\frac{Q}{t} =\frac{KA\delta T}{d}

where Q is amount of heat flowing in time t through area A and  a medium of thickness d having two faces at temperature difference δT . K is thermal conductivity of the medium .

Here Q = 3.34 x 10⁶/6 , t = 24 x 60 x 60 = 86400 s , A = .332 X .332 = .0110224 m² ,  δT = 104.7

Put these values here

\frac{3.34\times10^6}{6\times86400}= \frac{k\times.011224\times104.7}{4.41\times10^{-2}}

K=\frac{3.34\times4.41\times10^4}{6\times86400\times.011224\times104.7}

K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹

4 0
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