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anyanavicka [17]
3 years ago
5

A 3 kilogram cat is resting on top of a bookshelf that is 1 meters high. What is the cat’s gravitational potential energy relati

ve to the floor?
Physics
1 answer:
AVprozaik [17]3 years ago
6 0

We have: Gravitational Potential Energy (U) = mgh

Here, m = 3 Kg

g = 9.8 m/s²        [ constant value for earth system ]

h = 3 m


Substitute their values into the expression:

U = 3 × 9.8 × 3

U = 88.2 J


In short, Your Answer would be 88.2 Joules


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Answer:

Second order line appears at 43.33° Bragg angle.

Explanation:

When there is a scattering of x- rays from the crystal lattice and interference occurs, this is known as Bragg's law.

The Bragg's diffraction equation is :

n\lambda=2d\sin\theta      .....(1)

Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.

Given :

Wavelength, λ = 1.4 x 10⁻¹⁰ m

Bragg's angle, θ = 20°

Order of constructive interference, n =1

Substitute these value in equation (1).

1\times1.4\times10^{-10} =2d\sin20

d = 2.04 x 10⁻¹⁰ m

For second order constructive interference, let the Bragg's angle be θ₁.

Substitute 2 for n, 2.04 x 10⁻¹⁰ m for d and 1.4 x 10⁻¹⁰ m for λ in equation (1).

2\times1.4\times10^{-10} =2\times2.04\times10^{-10} \sin\theta_{1}

\sin\theta_{1} =0.68

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2 years ago
A car accelerates at a rate of 3 m/s^2. If it's original speed is 8 m/s, how many seconds will it take the car to reach a final
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The 8 kg block is then released and accelerates to the right, toward the 2 kg block. The surface is rough and the coefficient of
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Answer:

3.258 m/s

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Energy stored in spring is given by

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The speed of the 8 kg block just before collision is 3.258 m/s

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