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OLga [1]
2 years ago
11

When the forces acting moving body are balanced the net force becomes zero. As a result the body will:

Physics
1 answer:
WINSTONCH [101]2 years ago
5 0

Answer:

<h2>a</h2><h2> move with an increasing velocity</h2>
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bearhunter [10]

Answer:

The answer is A but I could be wrong

8 0
2 years ago
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If the force is 4 newtons between two charged spheres separated by 3 centimeters, calculate the force between the same spheres s
il63 [147K]

Answer:

1 Newton

Explanation:

F=9*10^9*q0q1/r^2]]

F=9*10^9*(q0q1)/ r^2

r=3cm

F=4N

F=9*10^9*(q0q1)/3^2

4=9*10^9*(q0q1)/9

4=10^9 q0q1

q0q1=4/10^9

q0q1=4*10^-9

To calculate the force between the forces at a distance of 6 cm

F=9*10^9*(q0q1)/ r^2

=9*10^9*(4*10^-9)/6^2

=9*10^9*(4*10^-9)/36

=10^9*4*10^-9/4

=10^9*10^-9

=1 Newton

7 0
2 years ago
Calculate delta g for the reaction if the partial pressures of the initial mixture are pcl5 = .0029 atm, pcl3 = .27 atm, and pcl
AnnyKZ [126]

Answer: equation for the reaction is given below

PCL2+PCL3=PCL5

Where pcl2=0.40atm,pcl3=0.27atm

Pcl5=0.0029atm

Using ∆G=-RTin(PCL5/PCl2*PCL3)

Where R=8.314J/K/mol and T=298K

∆G=-8.314*298in(0.0029/0.40*.27)

∆G=8962.6J/mol

Explanation:

7 0
3 years ago
calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30 metre per seco
Anna71 [15]

Answer:

height is 45 metres

Explanation:

KE=PE

¹/²mv² = mgh

¹/²v² = gh

but v =30m/s

(30)² / 2 =10h

450=10h

h = 45m

5 0
3 years ago
1. What are the two factors affecting friction
bija089 [108]
Answer: a.) Roughness of the surfaces in contact with each other .
Higher the roughness of surfaces in contact with each other, greater is the friction between bodies. Force of friction will be less between smooth surfaces.

b.) Weight of the sliding/rolling body: greater the weight of the moving body on the surface, more is the force of friction on the body by the surface.

I hope this helps

5 0
1 year ago
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