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dimulka [17.4K]
3 years ago
8

As the proton approaches the uranium nucleus, the repulsive force slows down the proton until it comes momentarily to rest, afte

r which the proton moves away from the uranium nucleus. How close to the uranium nucleus does the proton get
Physics
1 answer:
Klio2033 [76]3 years ago
3 0

Answer:

 r^2 = \frac{ 2 k  \ Ze^2}{ 2m}

Explanation:

For this exercise we must use the principle of conservation of energy

starting point. The proton very far from the nucleus

          Em₀ = K = ½ m v²

final point. The point where the proton is stopped (v = 0)

          Em_f = U = q V

where the potential is

          V = k Ze / r²

Let us consider that all the charge of the nucleus is in the center, therefore r is the distance from this point to the proton that is approaching

Energy is conserved

          Em₀ = Em_f

           ½ m v² = e (k \frac{Ze}{r^2})

          r^2 = \frac{ 2 k  \ Ze^2}{ 2m}

with this expression we can find the closest approach distance (r)

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Which of the following is not one of the observed characteristics of our solar system?
Sindrei [870]
<span>The characteristic not observed is the sun and planets rotate in the same direction. The planets in the solar system go around the sun. The sun is in a fixed position relative to planets. The time one planet takes to go around the sun is a year on that planet. the suns gravity keeps the solar system together and th planets revolving aroud it </span>
3 0
3 years ago
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A steel rod is pulled in tension with a stress that is less than the yield strength. The modulus of elasticity may be calculated
pshichka [43]

Answer:

B. Axial stress divided by axial strain

Explanation:

Elasticity:

It is the tendency of an object to deform along the axis when an opposing force is applied without facing permanent change in shape.

Plasticity:

When an object crosses the elasticity limit, it enters plasticity where the change due to stress is permanent and the object might even break.

Yield strength:

Yield strength is the point of maximum bearable stress that indicates the limit of elasticity.

Our case:

As the stress applied is less than the yield strength, the rod is still in the elasticity state and its modulus can be calculated.

Modulus of Elasticity = Stress along axis/Ratio of change in length to original length

Axial strain is basically the ratio of change in length to original length.

So, Modulus of Elasticity = Axial Stress/ Axial Strain

6 0
3 years ago
You are pushing a box up a ramp with 70 N of force. If the ramp is made steeper and shorter, what needs to happen to the box for
Elenna [48]

Answer:

A larger force than 70 N will be required for the box to continue moving

Explanation:

A ramp is an inclined plane surface that is tilted to form a slope on its opposite sides

A ramp provides mechanical advantage or force amplification, by allowing less force to lift heavier load from having to move through a longer distance to reach a particular elevation when the slope of the ramp is gentle

Therefore, when the slope is steeper, and shorter, more force than 70 N will be required for the box to continue moving.

6 0
3 years ago
What does the rotational speed of the ring module have to be so that an astronaut standing on the outer rim of the ring module f
Usimov [2.4K]

Complete question:

In the movie The Martian, astronauts travel to Mars in a spaceship called Hermes. This ship has a ring module that rotates around the ship to create “artificial gravity” within the module. Astronauts standing inside the ring module on the outer rim feel like they are standing on the surface of the Earth. (The trailer for this movie shows Hermes at t=2:19 and demonstrates the “artificial gravity” concept between t= 2:19 and t=2:24.)

Analyzing a still frame from the trailer and using the height of the actress to set the scale, you determine that the distance from the center of the ship to the outer rim of the ring module is 11.60 m

What does the rotational speed of the ring module have to be so that an astronaut standing on the outer rim of the ring module feels like they are standing on the surface of the Earth?

Answer:

The rotational speed of the ring module have to be 0.92 rad/s

Explanation:

Given;

the distance from the center of the ship to the outer rim of the ring module r, = 11.60 m

When the astronaut standing on the outer rim of the ring module feels like they are standing on the surface of the Earth, then their centripetal acceleration will be equal to acceleration due to gravity of Earth.

Centripetal acceleration, a = g = 9.8 m/s²

Centripetal acceleration, a = v²/r

But v = ωr

a = g = ω²r

\omega = \sqrt{\frac{g}{r}} = \sqrt{\frac{9.8}{11.6} } = 0.92 \ rad/s

Therefore, the rotational speed of the ring module have to be 0.92 rad/s

3 0
3 years ago
A rope is vibrating so as to form the standing wave pattern shown. How many antinodes are present in the rope?a- 5b- 4c- 8d- 10e
denpristay [2]

c) 8

Explanation

When you shake a rope, the particles in the rope move up and down, and the wave moves forward or away from the source of energy. The rope moves in a direction that is perpendicular

Nodes are the places where the rope doesn't move at all; antinodes occur where the motion is greatest.

Step 1

let's check the graph:

a) Nodes

and Antinodes

so, in the ripe there are 8 antinodes

therefore, the answer is

c) 8

I

4 0
1 year ago
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