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Fofino [41]
3 years ago
11

The range is the horizontal distance from the cannon when the pumpkin hits the ground. This distance is given by the product of

the horizontal velocity (which is constant) and the amount of time the pumpkin is in the air (which is determined by the vertical component of the initial velocity, as you just discovered). Set the initial speed to 14 m/s, and fire the pumpkin several times while varying the angle between the cannon and the horizontal. For which angle is the range a maximum (with the initial speed held constant)?
Angle:
0
60
45
90
30
Physics
1 answer:
jarptica [38.1K]3 years ago
3 0

The answer is 45 degrees.  I am not doing a field experiment for you that involves a cannon and a day's work, for 5 points.

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zavuch27 [327]
Yes I pretty sure it's c
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3 years ago
explain why conductors and insulators are both required to construct the electrical wiring in your home
olchik [2.2K]
Conductors (something that allows electricity to flow easily) allow for electricity to flow easily. This would be the wires. If you don't have conductors, then you cannot have electricity flow.

Insulators (something that doesn't allow electricity to flow through it) is important because it allows us to be able to touch the cables or place them next to one another and not shock ourselves

Hope this helps
6 0
4 years ago
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⦁ What is the mass of air in a room that has dimensions of 10m x 20m x 4 m? Use values from the book to show your work.
agasfer [191]
The mass of an air can be derived from the equation from density, where D=m/v. Multiply each sides by v making the equation m= Dv. Substituting the values for density and volume. m = (1.225 kg/m3)(10x20x4)m3 gives a result of 980 kg.
8 0
4 years ago
Two wooden boxes of equal mass but different density are held beneath the surface of a large container of water. Box A has a sma
Helga [31]

Answer:

<em>Which box has the greater acceleration?</em>

E. Box A

Explanation:

<em>The question is incomplete:</em>

<em>Which box has the greater acceleration?</em>

The bouyant force exerted by the water is equal in both boxes, because it depends on the volume displaced (that is the same for both boxes) and the density of the water.

But, the weight of each boxes is different, according to their density.

For the Box A the acceleration will be:

m_aa_a=gV(\rho_w-\rho_a)\\\\\rho_aVa_a=gV(\rho_w-\rho_a)\\\\a_a=g\frac{(\rho_w-\rho_a)}{\rho_a}

The same applies for the Box B:

a_b=g\frac{(\rho_w-\rho_b)}{\rho_b}

If we express the ratio of the accelerations, we have:

a_a/a_b=\frac{(\rho_w-\rho_a)}{\rho_a}*\frac{\rho_b}{(\rho_w-\rho_b)}\\\\

a_a/a_b=\frac{(\rho_w-\rho_a)}{(\rho_w-\rho_b)} \frac{\rho_b}{\rho_a}

We know that both densities are lower than water, because they accelerate upward to the surface when they are released (if they were more dense than water, they would sink more).

We will treat the densities as relative to water, so it becomes rho_w=1.

If we distribute the product, and know that the density of B is higher than the density of A, and both are higher than the product of the densities, we have:

\rho_w=1\\\\\frac{a_a}{a_b}=\frac{(1-\rho_a)}{(1-\rho_b)} \frac{\rho_b}{\rho_a}=\frac{\rho_b-\rho_a\rho_b}{\rho_a-\rho_a\rho_b}\\\\\\\rho_b>\rho_a>\rho_a\rho_b>0\\\\\\\frac{a_a}{a_b}=\frac{\rho_b-\rho_a\rho_b}{\rho_a-\rho_a\rho_b}>1\\\\a_a>a_b

The acceleration of A is higher than the acceleration of B.

7 0
3 years ago
Which of the following is the best example of an object in free fall?
SashulF [63]
The answer is D because theres nothing stopping that person from falling
5 0
3 years ago
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