Answer:
6 days
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Half life (t½) =?
Next, we shall determine the decay constant. This can be obtained as follow:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Decay constant (K) =?
Log (N₀/N) = kt / 2.303
Log (100/6.25) = k × 24 / 2.303
Log 16 = k × 24 / 2.303
1.2041 = k × 24 / 2.303
Cross multiply
k × 24 = 1.2041 × 2.303
Divide both side by 24
K = (1.2041 × 2.303) / 24
K = 0.1155 /day
Finally, we shall determine the half-life of the isotope as follow:
Decay constant (K) = 0.1155 /day
Half life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 0.1155
t½ = 6 days
Therefore, the half-life of the isotope is 6 days
Answer:
Degrees Kelvin = Degrees Celsius + 273.15
Degrees Kelvin = -13 + 273.15
= 260.15
°
Explanation:
Answer:
It's the third option.
Explanation:
In order for the chemical equation to be correctly it needs the same number of atoms of each element on both sides of the equal sign
Answer:
true
Explanation:
H2O : 2 covalent bonds are established between O atom and 2 H atom (H--O--H) by mutual shearing of their valence electrons.
Answer:
Weathering involves the use of water and or wind to wear down the environment. The sand dunes were most likely carried by wind to form them and form its shape. Erosion most likely took away parts of the sand to make the sand dune. Deposition most likely deposited sand to the area.
Explanation:
If you possibly want a better explanation, try looking it up :).
#teamtrees #WAP (Water And Plant)
