Answer:
c. 40200 J
Explanation:
Assume gravitational constant g = 9.8m/s2. The weight of the 2000kg vehicle is
![W = mg = 2000*9.8 = 19600 N](https://tex.z-dn.net/?f=W%20%3D%20mg%20%3D%202000%2A9.8%20%3D%2019600%20N)
In addition to the friction averaging at 500N, the total force is
F = 20000 + 500 = 20100 N
The work required to generate this force over a distance of 2m would be
F*s = 20500 * 2 = 40200 J
So c.40200 J is the correct answer
Answer:
Explanation:
We need to use the momentum and energy conservation.
![p_{0}}=p_{f}](https://tex.z-dn.net/?f=p_%7B0%7D%7D%3Dp_%7Bf%7D)
Where:
- m is the mass of bullet (m=0.01 kg)
- M is the mass of the wooden (M=0.75 kg)
- v(0) initial velocity of bullet
- V(1) is the velocity of the combined object in the moment the bullet hist the block
Conservation of energy.
We have kinetic energy at first and kinetic and potential energy at the end.
![(1/2)(m+M)V_{1}^{2}=(1/2)(m+M)V_{2}^{2}+(m+M)gh](https://tex.z-dn.net/?f=%281%2F2%29%28m%2BM%29V_%7B1%7D%5E%7B2%7D%3D%281%2F2%29%28m%2BM%29V_%7B2%7D%5E%7B2%7D%2B%28m%2BM%29gh)
Here:
- V(1) is the velocity of the combined at the initial position
- h is the vertical height ( h = 0.800 m)
We can find V(2) using the definition of force at this point:
![\Sigma F=(m+M)a_{c}=(m+M)(V_{2}^{2}/R)](https://tex.z-dn.net/?f=%5CSigma%20F%3D%28m%2BM%29a_%7Bc%7D%3D%28m%2BM%29%28V_%7B2%7D%5E%7B2%7D%2FR%29)
![T-(m+M)gcos(\theta)=(m+M)a_{c}=(m+M)(V_{2}^{2}/R)](https://tex.z-dn.net/?f=T-%28m%2BM%29gcos%28%5Ctheta%29%3D%28m%2BM%29a_%7Bc%7D%3D%28m%2BM%29%28V_%7B2%7D%5E%7B2%7D%2FR%29)
Now, we can solve the equation to find V(2)
![V_{2}=\sqrt{\frac{R*(T-(m+M)*g*cos(\theta))}{(m+M)}}](https://tex.z-dn.net/?f=V_%7B2%7D%3D%5Csqrt%7B%5Cfrac%7BR%2A%28T-%28m%2BM%29%2Ag%2Acos%28%5Ctheta%29%29%7D%7B%28m%2BM%29%7D%7D)
![V_{2}=\sqrt{\frac{1.72*(4.86-(0.01+0.75)*9.81*cos(57.66))}{(0.01+0.75)}}](https://tex.z-dn.net/?f=V_%7B2%7D%3D%5Csqrt%7B%5Cfrac%7B1.72%2A%284.86-%280.01%2B0.75%29%2A9.81%2Acos%2857.66%29%29%7D%7B%280.01%2B0.75%29%7D%7D)
Now we can find V(1) using the conservation of energy equation
![(1/2)V_{1}^{2}=(1/2)V_{2}^{2}+gh](https://tex.z-dn.net/?f=%281%2F2%29V_%7B1%7D%5E%7B2%7D%3D%281%2F2%29V_%7B2%7D%5E%7B2%7D%2Bgh)
Finally, using the momentum equation we find v(0)
I hope it helps you!
I believe the right answer choice is letter B
C.electron
because only electron spin or work around the Nucleas
Answer: 60.56
Explanation: Just multiply 3.785 by 16.