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Afina-wow [57]
3 years ago
7

Someone please help me

Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Answer:

1/49 it is the equal to that

Step-by-step explanation:

I

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Please help with trig question
swat32

The interior angles in any triangle sum to 180 degrees, so the measure of angle E is 180 - 65 - 50 = 65 degrees.

Assuming side d is opposite angle D, side e is opposite angle E, and side f is opposite angle F, we can use the law of sines to determine the side lengths e and f.

\dfrac{\sin D}d=\dfrac{\sin E}e=\dfrac{\sin F}f

\dfrac{\sin50^\circ}{7.5}=\dfrac{\sin65^\circ}e\implies e\approx8.87

Angles E and F have the same measure, so f\approx8.87 as well.

8 0
3 years ago
How can I solve this
Evgen [1.6K]

Answer:

\frac{a^{5}b }{x^{6} }

Step-by-step explanation:

you just need to forget about 0 because whole equation is raised to 0

and anything raise to 0 is 1

so

\frac{a^{5}b^{4}  }{x^{6}b^{3}  }  law of exponent a^{n} ÷ a^{m} = a^{n-m}

here b^{4} ÷ b^{3} = b^{4-3}

       = b^{1}

so the answer will be

\frac{a^{5}b }{x^{6} }

4 0
3 years ago
Maria finds a local gym that advertises 44 training sessions for $1393. Find the cost of 136 training sessions.
fiasKO [112]

Answer:

$4305.60

Step-by-step explanation:

1393 divided by 44 = 31.6590909

that's how much for one training session

so to find the pay for 136 sessions you need to do 31.6590909 x 136

which is 4305.63636

if you round that, you get $4305.60

6 0
3 years ago
Help me please this is due by 4:00 p.m today
Irina18 [472]

Answer:

8. 500.8

9. 5008

10. 50080

Step-by-step explanation:

8 0
3 years ago
I actually don’t get this and I have a test in 2 days please help what is g(x) and how
nataly862011 [7]

first off, is noteworthy that's the graph of an exponential function, thus the function will be along the lines of g(x) = abˣ , now, what's "a" and "b" values?

well, let's take a peek when x = 0 and x = 1.

\bf g(x) = ab^x \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 0\\ y = 1 \end{cases}\implies 1=ab^0\implies 1=a(1)\implies \boxed{1=a} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 1\\ y = 4 \end{cases}\implies 4 = ab^1\implies 4=1b^1\implies \boxed{4=b} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill g(x) = 4^x\qquad \qquad \qquad \begin{array}{|c|c|ll} \cline{1-2} x&y\\ \cline{1-2} -2&\frac{1}{4^2}\to \frac{1}{16}\\ -1&\frac{1}{4}\\ 0&1\\ 1&4\\ 2&16\\ \cline{1-2} \end{array}~\hfill

8 0
3 years ago
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