Answer:
Maximum weight that can be lifted = 18,000 N
Explanation:
Given:
Cross-sectional area of input (A1) = 0.004 m²
Cross-sectional area of the output (A2) = 1.2 m
²
Force (F) = 60 N
Computation:
Pressure on input piston (P1) = F / A1
Assume,
Maximum weight lifted by piston = W
Pressure on output piston (P2) = W / A2
We, know that
P1 = P2
[F / A1] = [W / A2]
[60 / 0.004] = [W / 1.2]
150,00 = W / 1.2
Weight = 18,000 N
Maximum weight that can be lifted = 18,000 N
Answer:
Explanation:
Given data
Terminal velocity for spread eagle position vt=130 km/h
Terminal velocity for nosedive position vt=326 km/h
The terminal speed of the diver is given by
Therefore the area is given by
Since everything else is constant in the two dives except for the terminal velocity, the ratio between the area in the slow position to the area in the fast position is
Answer:
opinion a
Explanation:
the si units of distance is metre (m)
1. Make an observation
2. Form a question
3. Form a hypothesis
4. Conduct an experiment
5. Analyze the data and draw your conclusion
