C,H. + 020 H2O + CO2<br> How many grams of O, are needed to<br> combust 55.0 grams of CHỞ?

What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?

devlian [24]

Answer:

$T = 0.182$ Kelvin

Explanation:

As we know that

$PV = nRT\\$

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin

R is the gas constant

V is the volume in liters

$R = 0.08206$

Substituting the given values in above equation, we get -

$1.35 * \frac{50}{1000}= 4.5 * 0.08206* T\\$

On rearranging, we get

$T = \frac{1.35*50}{1000*0.08206*4.5} \\$

$T = 0.182$ Kelvin

7 0

3 years ago

What is the empirical formula for P4O10?

Sphinxa [80]

Answer: P2O5

Explanation: You divide both subscripts by 2 to get the empirical formula.

8 0

3 years ago

Read 2 more answers

What is the third ionization energy of titanium?

-Dominant- [34]

Ti^2+(g)-->Ti^3+(g)+-3rd IP=2652.5

5 0

3 years ago

How a cation is formed by an atom?

fenix001 [56]

Answer:

Cations are positively charged atoms and hence we need to make the atom positively charged in order to get a cation

We know that an atom is neutral as a whole, so we have equal number of electrons and protons

since we cannot mess with the number of protons in an atom, we have to do it by altering the number of electrons

If we reduce the amount of electrons in an atom, the net charge will be positive and hence a cation will be formed

4 0

3 years ago

There are 31.1 grams (g) in 1 troy ounce (ozt). How many ozt of gold are extracted from 1 short ton of average Nevada ore

devlian [24]

This problem is providing us with the mass equivalent to one troy ounce. Thus, the troy ounces of gold in one short ton of average Nevada ore is required and found to be the 0.103 otz according to the following dimensional analysis.

<h3>Dimensional analysis</h3>

In chemistry, a raft of problems do not always provide an equation in order to be solved yet dimensional analysis can be applied, so as to obtain the desired amount in the required units.

Thus, since this problem asks for try ounces in an average Nevada ore, which has 3.2 grams of gold per short ton of ore, one can solve the following setup in order to obtain the required answer in otz:

$\frac{3.2gAu}{1short-ton}*1short-ton*\frac{1otz}{31.1g} \\$

Where the short tons are cancelled out as well as the grams, in order to obtain:

$0.103 otz$

Learn more about dimensional analysis: brainly.com/question/10874167

4 0

2 years ago

C,H. + 020 H2O + CO2 How many grams of O, are needed to combust 55.0 grams of CHỞ?