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Andrei [34K]
2 years ago
5

Need help with this question ​

Physics
2 answers:
lakkis [162]2 years ago
5 0

Answer:

1.39m

Explanation:

Vikentia [17]2 years ago
4 0
Steps:

Abbreviations:
T= Time
Vf = Final Velocity
Vo = Initial Velocity
Δx = Displacement (aka distance)
| … | = Absolute Value

Here is 1 Equation for Time
T= (Vf/a) - (Vo/a)

T= | (0/-9.81) - (2.78/-9.81) |
T = 0.283

Time up is the same as time down so multiply by 2.
0.283 * 2 = 0.57

Here is 1 Equation for Displacement
Δx = 0.5 * t^2 * a

Δx = | 0.5 * 0.57^2 * -9.81 |
Δx = 1.58

Answer:
Option C
1.58
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Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.00×104 Pa . Assum
cestrela7 [59]

Answer:

T_{2}=278.80 K

Explanation:

Let's use the equation that relate the temperatures and volumes of an adiabatic process in a ideal gas.

(\frac{V_{1}}{V_{2}})^{\gamma -1} = \frac{T_{2}}{T_{1}}.

Now, let's use the ideal gas equation to the initial and the final state:

\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}

Let's recall that the term nR is a constant. That is why we can match these equations.  

We can find a relation between the volumes of the initial and the final state.

\frac{V_{1}}{V_{2}}=\frac{T_{1}p_{2}}{T_{2}p_{1}}

Combining this equation with the first equation we have:

(\frac{T_{1}p_{2}}{T_{2}p_{1}})^{\gamma -1} = \frac{T_{2}}{T_{1}}

(\frac{p_{2}}{p_{1}})^{\gamma -1} = \frac{T_{2}^{\gamma}}{T_{1}^{\gamma}}

Now, we just need to solve this equation for T₂.

T_{1}\cdot (\frac{p_{2}}{p_{1}})^{\frac{\gamma - 1}{\gamma}} = T_{2}

Let's assume the initial temperature and pressure as 25 °C = 298 K and 1 atm = 1.01 * 10⁵ Pa, in a normal conditions.

Here,

p_{2}=8.00\cdot 10^{4} Pa \\p_{1}=1.01\cdot 10^{5} Pa\\ T_{1}=298 K\\ \gamma=1.40

Finally, T2 will be:

T_{2}=278.80 K

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3 years ago
How does the end point differ from the equivalence <br>point of a titration?​
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<u>Answer:</u>

<em>Equivalence point and end point are terminologies in pH titrations and they are not the same. </em>

<u>Explanation:</u>

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<em>A pH less than 7 will be the result if the resultant is acidic and if it is basic the pH will be greater than 7. </em>In a strong base-strong acid and weak base-weak acid titration the pH at the equivalence point will be 7 indicating <em>neutral nature of the solution. </em>

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