Question

When heated, calcium carbonate decomposes according to the equation given below:

Answer 1

Answer:

15.2L at STP

Explanation:

Given reaction expression;

         CaCO₃ → CaO + CO₂

Number of moles of CaCO₃  = 0.68mol

Unknown:

Volume of CO₂ produced at STP = ?

Solution:

To solve this problem, we must first find the number of moles CO₂ produced,

     1 mole of CaCO₃ will produce 1 mole of CO₂

   0.68mole of CaCO₃ will produce 0.68mole of CO₂ at STP

Now;

             1 mole of gas occupies a volume of 22.4L at STP;

           0.68mole of CO₂ will then occupy 0.68 x 22.4  = 15.2L at STP