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mojhsa [17]
3 years ago
10

How many moles of carbon dioxide gas can be produced when 7.94 moles of benzene (C6H6) react with excess oxygen? Be sure to show

the work that you did to solve this problem.
Unbalanced equation: C6H6 + O2 “yields”/ CO2 + H2O

I really need this fast!!! please
Chemistry
1 answer:
Sliva [168]3 years ago
6 0
The balanced equation is 

<span>2 C6H6 +15 O2 = 12 CO2 + 6 H2O </span>

<span>the ratio between C6H6 and CO2 is 2 : 12 </span>

<span>moles CO2 produced = 7.94 x 12 / 2 =47.6</span>
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Calculate δg∘rxn and e∘cell for a redox reaction with n = 3 that has an equilibrium constant of k = 4.4×10−2. you may want to re
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a) First, to get ΔG°rxn we have to use this formula when:

ΔG° = - RT ㏑ K 

when ΔG° is Gibbs free energy 

and R is the constant = 8.314 J/mol K

and T is the temperature in Kelvin = 25 °C+ 273 =  298 K 

and when K = 4.4 x 10^-2

so, by substitution:

ΔG°= - 8.314 * 298 *㏑(4.4 x 10^-2)

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b) then, to get E
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and F is Faraday constant = 96485 C/mol

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In acetyl CoA formation, the carbon-containing compound from glycolysis is oxidized to produce acetyl CoA. From the following co
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Explanation:

Hello,

In this case, it is important to recall that acetyl-CoA is produced either by oxidative decarboxylation of pyruvate derived from glycolysis, which is carried out into the mitochondrial matrix, by cause of the oxidation of high-order fatty acids, or by oxidative degradation of very specific amino acids. Acetyl-CoA then enters in the citric acid cycle where it is oxidized in the light of energy production.

In this manner, during such processes, there are some net inputs and outputs, therefore, they are sorted as show below, considering there some of them not classified neither as input nor output:

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- Not input or output: O₂, ADP, glucose and ATP

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