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stealth61 [152]
3 years ago
14

Look at the questions below and decide which is declarative.

Chemistry
1 answer:
Yuliya22 [10]3 years ago
3 0
Im not sure but here is some information to help A declarative question is a yes-no question that has the form of a declarative sentence but is spoken with rising intonation at the end. Declarative sentences are commonly used in informal speech to express surprise or ask for verification.
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There are 1.204 x 10^24 atoms of oxygen. How many moles is this?
Nastasia [14]

Answer:

7.25 x 10^47

Explanation:

1.204 x 10^24 moles*6.022 x 10^23 avogadro's number= 7.25 x 10^

7 0
3 years ago
How do you know how to order an empirical formula?
inessss [21]

Answer:

Start with the number of grams of each element, given in the problem. the mass of each element = the percent given. Convert the mass of each element to moles using the molar mass from the periodic table. Divide each mole value by the smallest number of moles calculated.

3 0
2 years ago
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uysha [10]
The answer is double displacement is the answer
3 0
3 years ago
A scientist stores a very large number of particles in a container. In order to determine the number of particles, the scientist
Leni [432]

When the temperature and the volume of the gas stored in the container are high then the number of the moles will be measured accurately. Thus, options A and B are correct.

<h3>What is the ideal gas law?</h3>

The ideal gas law is the establishment of the relation between the elements like the moles, pressure, temperature, and the volume of the gas containing the particle.

The ideal gas states:

PV = nRT

With an increase in the temperature, the number of particles that collides increases as the kinetic energy increases. The particle of the container is more when the volume of the gas is more.

Therefore, in options A and B high temperature and volume increase the accuracy.

Learn more about ideal gas here:

brainly.com/question/14552813

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6 0
2 years ago
Consider the reaction of diboron trioxide with carbon and chlorine. B2O3 (s) + 3C (s) + 3Cl2 (g) 2BCl3 (g) + 3CO (g) Determine t
Sholpan [36]

Answer:

Limiting reactant = B2O3

Amount of BCl3 formed = 468 g

Explanation:

The given reaction is:

B2O3 (s) + 3C (s) + 3Cl2 (g) \rightarrow 2BCl3 (g) + 3CO (g)

In order to identify the limiting reagent calculate the moles of B2O3, C and Cl2. The reagent with the lowest moles is the limiting reactant

Moles(B2O3)=\frac{Mass(B2O3)}{Mol.wt(B2O3)}=\frac{139g}{69.6g/mol}=1.997moles

Moles(C)=\frac{Mass(C)}{At.wt(C)}=\frac{87.8g}{12g/mol}=7.317moles

Moles(Cl2)=\frac{Mass(Cl2)}{Mol.wt(Cl2)}=\frac{650g}{70.9g/mol}=9.168moles

Since the moles of B2O3 < C < Cl2, the limiting reactant is B2O3

Based on the reaction stoichiometry:

1 mole of B2O3 produces 2 moles of BCl3

Hence, the number of moles of BCl3 produced under the experimental conditions = 2*1.997=3.994 moles

Mass(BCl3)= Moles* Mol.wt = 3.994 moles*117.17g/mol = 468 g

8 0
3 years ago
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