Taking into accoun the STP conditions and the ideal gas law, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.
First of all, the STP conditions refer to the standard temperature and pressure, where the values used are: pressure at 1 atmosphere and temperature at 0°C. These values are reference values for gases.
On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
- P is the gas pressure.
- V is the volume that occupies.
- T is its temperature.
- R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
- n is the number of moles of the gas.
Then, in this case:
- P= 1 atm
- V= 44.1 L
- n= ?
- R= 0.082
- T= 0°C =273 K
Replacing in the expression for the ideal gas law:
1 atm× 44.1 L= n× 0.082 × 273 K
Solving:
n=1.97 moles
Being the molar mass of O₂, that is, the mass of one mole of the compound, 32 g/mole, the amount of mass that 1.97 moles contains can be calculated as:
= 63.04 g ≈ <u><em>63 g</em></u>
Finally, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.
Learn more about the ideal gas law:
Every organic molecules/compound contains carbon (c).
Some other very abundant are hydrogen, nitrogen, oxygen, phosphorus, and sulfur.
I learned this with the acronym CHNOPS.
C - Carbon
H - Hydrogen
N - Nitrogen
O - Oxygen
P - Phosphorus
S - Sulfur
Hope this helps!
Answer:
The answer is 529.6 g
Explanation:
I took the test and somehow got it right :0 but yea this is the correct answer. I hope this helps :)
The answer is (in
order from strongest to weakest);
<span>covalent </span>
<span>ionic </span>
ion-dipole
H-bonding
dipole-dipole
<span>van der Waals</span>
A covalent<span> bond is
hardest to break because it involves sharing of electrons by atoms while Van der
Waals is weakest because they involve electrostatic
attraction due to differentially induced
dipoles between atoms and its strength is dependent
on their distance apart. </span>
Answer:
Single displacement and reduction
Explanation:
In a single-displacement reaction, one element exchanges partners with another.
This is a single-displacement reaction, because the element Ca exchanges partners with H.
This is also a reduction/oxidation (redox) reaction, because the optically active of Ca increases from 0 to +2 (oxidation), while the oxidation number of H decreases from +1 to 0 (reduction),
The most common types of reactions are:
- Combination
- Decomposition
- Single displacement
- Double displacement
- Reduction/oxidation
