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hichkok12 [17]
3 years ago
5

BRAINLIESTTT ASAP!! PLEASE HELP ME ASAP!

Chemistry
1 answer:
Alexandra [31]3 years ago
4 0

Answer:

Single displacement and reduction

Explanation:

In a single-displacement reaction, one element exchanges partners with another.

\rm Ca + 2H$_2$O $\longrightarrow$ Ca(OH)$_2$ + H$_2$

This is a single-displacement reaction, because the element Ca exchanges partners with H.

This is also a reduction/oxidation (redox) reaction, because the optically active of Ca increases from 0 to +2 (oxidation), while the oxidation number of H decreases from +1 to 0 (reduction),

The most common types of reactions are:

  • Combination
  • Decomposition
  • Single displacement
  • Double displacement
  • Reduction/oxidation
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What is the molarity of a solution that contains 0.400 mol HCl in 9.79 l solution?
Maslowich

Answer:

  • Option B, 0.0409 M

Explanation:

<u>1) Data:</u>

a) M = ?

b) n = 0.400 mol

V = 9.79 liters

<u>2) Formula:</u>

  • M = n / V (in liters)

<u>3) Solution:</u>

  • M = 0.400 mol / 9.79 liter = 0.04086 M

  • Since each data contain 3 significant digits, the answer must be reported with 3 significant digits. So, the correct answer is 0.0409 M, which is the option B.
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4 years ago
In part A of the experiment you will need to make a 4.80 x 10-4 M KSCN solution starting with a 2.00 x 10-3M KSCN solution. You
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Answer:

Answer to you need to make a 6.00 x 10-4 M KSCN solution starting with a 2.00 x 10-3 M KSCN solution. You will be making up the so. ... X 10-3 M KSCN Solution. You Will Be Making Up The Solution In A 25 ML Volumetric Flask And Using 0.5 M HNO3 As The Diluent. What Volume Of 2.00 X 10-3 M KSCN Will You Need?

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4 years ago
Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas and an aque
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Explanation:

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The chemical reaction of the above is denoted by,

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Mg went from a 0 to a +2 state which would mean that it lost electrons.

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Please do react or comment if you need clarification or if the answer helped you. This can help other users as well. Thank you.

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