Answer:
(a) 0.014 A
(b) 2 V
Explanation:
(a) Applying
V = IR'...................... Equation 1
Where V = Voltge, I = current, R = total resistance.
make I the subject of the equation
I = V/R'................... Equation 2
From the question,
Given: V = 12 V, R' = (122+232+500) ohms (The resistance are connected in series) = 854 ohms
Substitute these values into equation 2
I = 12/854
I = 0.014 A
(b) Applying
V' = V(R₁)/(R₁+R₂+R₃)...................... Equation 3
Where V' = Voltage across the 100 ohms resistor.
From the question,
V = 12V, R₁ = 100 ohm, R₂ = 200 ohm, R₃ = 300 ohm.
Substitute these values into equation 3
V' = (12×100)/(100+200+300)
V' = 1200/600
V' = 2 V
