Answer:
, assuming that the speed of the electron stays the same.
Explanation:
Let denote the speed of this electron. Let denote the electric charge on this electron. Let denote the mass of this electron.
Since the path of this electron is a circle (not a helix,) this path would be in a plane normal to the magnetic field.
Let denote the strength of this magnetic field. The size of the magnetic force on this electron would be:
.
Assuming that there is no other force on this electron. The net force on this electron would be . By Newton's Second Law of motion, the acceleration of this electron would be:
.
On the other hand, since this electron is in a circular motion with a constant speed:
.
Combine the two equations to obtain a relationship between (radius of the path of the electron) and (strength of the magnetic field:)
.
Simplify to obtain:
.
In other words, if the speed of this electron stays the same, the radius of the path of this electron would be inversely proportional to the strength of the magnetic field. Doubling the radius of this path would require halving the strength of the magnetic field (to .)
Force = (mass) x (acceleration)
= (2 kg) x (20 m/s²) = 40 newtons .
about 9 pounds .
Note: The ball can only accelerate during the short time
that the clubface is in contact with it. Once it leaves the
clubface, it can't accelerate any more.
Also ... that's one heckuva golf ball. It weighs about 4.4 pounds !
10 newton east is the answer because the two force vector form 0 degree angle with each other
1.) when the distance between the two objects is dubled then the gravitational Force btw them is <u>reduced by 4 times</u> I.e it becomes 1/4 of original due to the <u>inverse square law.</u>
2.) because the distance from the center of earth and pole is less then the distance btw pole and equator that's why due to <u>inverse square law</u> .
the gravitational Force on object at equator is less then the object on poles.