2 years ago

Horizontal displacement?

Physics

1 answer:

Neporo4naja [7]2 years ago

5 0

Answer:

....

Explanation:

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What is the speed of a bobsled whose distance-time graph indicates that it traveled 117m in 25s

Scilla [17]

Speed= distance/time
speed=117/25
speed=4.68m/sec

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3 years ago

The cylindrical tub of a dryer in a laundromat rotates counterclockwise about a horizontal axis at 41.5 rev/min as it dries the

frozen [14]

Answer:

$\theta = 49.81^0$

Explanation:

Given that:

$\omega = 41.5 \ rev/min\\\\\omega = 41.5 *\frac{1}{60}* 2 \pi\\\\\omega = 4.45 \ rad/s\\\\\\diameter = 0.748 m$

If we let the piece of the close lose contact at ∠θ;

Then ; from force balance;

we have:

$\\\\mg sin \theta = \frac{mv^2}{r}\\\\sin \theta = \frac{2v^2}{dg}\\\\\theta = sin^{-1} (\frac{2v^2}{dg})$

where;

$v = \frac{\omega d}{2}\\\\v = \frac{4.45 *0.748}{2}\\\\v = 1.6643\\\\v^2 = 2.77$

Again:

$\theta = sin^{-1}(\frac{2v^2}{dg})\\\\\theta = sin^{-1}( \frac{2*2.77}{0.74*9.8})\\\\\theta = 49.81^0$

6 0

2 years ago

Please help- it’s a 15 point change to my grade.

Harman [31]

Answer: Everything except heat and density

Explanation:

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2 years ago

1. Why should you use scientific notation when writing big numbers?

Fynjy0 [20]

Answer:

It helps the answer look clean. It also makes the work easier to work with.

Explanation:

Instead of writing a lot of zeros, all you have to do is add exponents to the number to show how much the decimal moved.

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2 years ago

The human ear canal is about 2.3 cm long. If it is regarded as a tube open at one end and closed at the eardrum, what is the fun

mariarad [96]

Answer:

For the given conditions the fundamental frequency is 3728.26 Hertz

Explanation:

We know that for a pipe open at one end and closed at other end the fundamental frequency is given by

$f=\frac{V_{s}}{4L}$

where

f is the fundamental frequency

$V_{s}$ is the speed of sound in air in the surrounding conditions.

L = Length of the pipe

Applying values we get and using speed of sound as 343m/s we get

$f=\frac{343}{4\times 2.3\times 10^{-2}}=3728.26Hz$

7 0

2 years ago